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VladimirAG [237]
2 years ago
6

Is the equation x^3 - 2x^2 + 1 = 0 a quadratic equation?​

Mathematics
1 answer:
olga2289 [7]2 years ago
4 0

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((x3) - 2x2) + 2x) - 1 = 0

STEP

2

:

Checking for a perfect cube

2.1 x3-2x2+2x-1 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-2x2+2x-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 2x-1

Group 2: -2x2+x3

Pull out from each group separately :

Group 1: (2x-1) • (1)

Group 2: (x-2) • (x2)

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8/12 of the games are either sports or educational.
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How to explain how to plot the points P(4,10) and Q(9,3) in a coordinate plane?
SpyIntel [72]
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To rent a taxi in Los Angeles, the taxi service charges a flat rate of $11.20 and an additional $3.10 per mile driven. Write an
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<u>The equation is:</u>

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2 years ago
. A boat traveled 300 miles in 15 hours. What<br> rate did the boat travel in miles per hour?
Gala2k [10]

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8 0
3 years ago
Which point corresponds to the real zero of the graph of y=log3(x+2)-1?
insens350 [35]

The point that corresponds to the real zero of the graph of y=log3(x+2)-1 is (1, 0)

<h3>Logarithm function</h3>

Given the logarithmic function expressed as:

y=log3(x+2)-1

The point that  corresponds to the real zero of the graph is at the point where y = 0

log3(x+2)-1 = 0

log3(x+2) = 1

log3(x+2) = log3 3
x + 2  = 3

x = 3 - 2

x = 1

Hene the point that corresponds to the real zero of the graph of y=log3(x+2)-1 is (1, 0)

Learn more on logarithm function here: brainly.com/question/13473114

3 0
2 years ago
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