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aivan3 [116]
3 years ago
7

PLS HELP ASAP! WILL MARK BRAINLIEST sin ∠E = 20/21 20/29 21/29 21/20

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
7 0
21/20 D is correct :) ;)
MariettaO [177]3 years ago
5 0
D





.....bekwjsjskbdjdjwvdkdks
You might be interested in
I think u guys know what to do !!!
kotykmax [81]

Answer:

B, C

Step-by-step explanation:

7 - x = 18

A.

7 - 2x = 18 - x

126 - 14x = 324 - 18x

We are nowhere near the solution.

B.

-x = 11

x = -11

This works.

C.

7 = x + 18

-11 = x

This works.

D.

25 - x = 36

-25 + x = -36

This does not help.

E.

7 = x + 18

0 = x + 11

We still do not have a solution.

Answer: B, C

4 0
2 years ago
How to differentiate ?
Bas_tet [7]

Use the power, product, and chain rules:

y = x^2 (3x-1)^3

• product rule

\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}

• power rule for the first term, and power/chain rules for the second term:

\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}

• power rule

\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3

Now simplify.

\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) =  \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)

Differentiate both sides and you end up with the same derivative:

\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2

7 0
2 years ago
what are the minimum first quartile median third quartile and the maximum of the data set? 9,20,4,18,4,18,20,9
den301095 [7]
<u>Answers</u>
1. Minimum = 4
2. First quartile = 6.5
3. Median = 13.5
4. Third quartile = 19
5. Maximum = 20

<u>Explanation</u>
To calculate the measure of central tendency, you first arrange the set of the data in ascending order.  
The set of data given will be;
4, 4, 9, 9, 18, 18, 20, 20.

Part 1:
The minimum value of the data is 4.

Part 2:
The first quatile is the median of the lower half which is comprised by:
4, 4, 9, 9

1st quartile = (4+9)÷2
                  = 13÷2
                  = 6.5

Part 3:
Median of the data is;

Median = (9+18)÷2
              =27÷2
            = 13.5

Part 4:
3rd quartile is the median of the upper half which comprises of; 
18, 18, 20, 20.

3rd quartile = (18+20)÷2
                  = 48÷2
                   = 19

Part 5
The maximum of the set of data is 20.
7 0
3 years ago
Marcelo scored 7 points for his basketball team. This was 20% of his team’s points. How many points did his team score?
baherus [9]

Answer:

35

Step-by-step explanation:

20% = 7

Therefore, 100% = Total Points By Whole Team

20% x 5 = 100%

7 x 5 = 35 Points

5 0
3 years ago
Solve for x.
aivan3 [116]
X^3 = 216

by taking cubic root for both  sides

\sqrt[3]{x^3} =  \sqrt[3]{216}

x = 6
7 0
3 years ago
Read 2 more answers
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