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Lelu [443]
2 years ago
7

Bobby panned for gold for 5 hours on Monday. On Tuesday, he panned for double the time he panned on Monday. On Wednesday, he pan

ned for 2 more hours than he did on Tuesday. He took Thursday off. On Friday, he
panned for 5 hours. How many total hours did Bobby pan Monday through Friday?
Mathematics
1 answer:
podryga [215]2 years ago
5 0

Answer:

32 hours

Step-by-step explanation:

Monday: 5 hours

Tuesday: 5*2 = 10 hours

Wednesday: 10+2 = 12 hours

Thursday: 0 hours

Friday: 5 hours

Add up all of the hours:

5+10+12+0+5 = 32

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10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
In Canada, households spent an average of $80.63 CDN monthly for high-speed broadband access.24 Assume that the standard deviati
ELEN [110]

Answer:

Step-by-step explanation:

Assuming a normal distribution for the amount spent by Canadian households for high-speed broadband access, the formula for normal distribution is expressed as

z = (x - u)/s

Where

x = amount spent by the Canadian households.

u = mean amount spent monthly.

s = standard deviation

From the information given,

u = $80.63 CDN

s = $27.32 CDN

We want to find the probability that the average amount will exceed $85. It is expressed as

P(x greater than 85) = 1 - P(x lesser than or equal to 85)

For x = 85

z = (85 - 80)/27.32 = 0.18

Looking at the normal distribution table, the corresponding z score is 0.57142

P(x greater than 85) = 1 - 0.57142 = 0.43

3 0
3 years ago
X ( x + 4 ) − 3 = 4 ( x + 19.5 )
Studentka2010 [4]

Answer:

9

Step-by-step explanation:

7 0
2 years ago
segment CD has endpoints at C(0, 3) and D(0, 8). If the segment is dilated by a factor of 2 about point C, what is the length of
MatroZZZ [7]

The length of the image of the segment CD is 10 units if the segment CD has endpoints at C(0, 3) and D(0, 8).

<h3>What is a distance formula?</h3>

It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.

The distance formula can be given as:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have two points C(0, 3) and D(0, 8)

The distance between these two points:

d = √(8-3)²

d = 5 units

The length of the image of segments CD = dilation factor×length of CD

= 2×5

= 10 units

Thus, the length of the image of the segment CD is 10 units if the segment CD has endpoints at C(0, 3) and D(0, 8).

Learn more about the distance formula here:

brainly.com/question/18296211

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7 0
2 years ago
Identify any transformations (translations, reflections, rotations) that are used in each corporate logo below. Some logos may h
lord [1]

Answer:

Check below

Step-by-step explanation:

There are rigid transformations that produce congruent figures: translation, rotation, and one transformation that produces a similar figure, namely: Dilation.

1) Toyota: translation, and Dilation.

Two ellipses translated within a larger ellipse.

2) 2 Reflections, or 4 rotations of the pre-image

We have two ways of drawing this figure. Either by reflection of the right and the lower one or by rotation.

3) CBS: Dilation of the circumference, inside a rhombus.

4) Mitsubishi: Reflection about the y axis, Rotation for the figure up.

e) Reflection

f) Translation

6 0
3 years ago
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