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harina [27]
3 years ago
9

Shawn makes bracelets using stone beads. He buys the beads for $0.30 each. The wire used to make each bracelet costs $0.10. a. W

rite an equation to find the cost (C) to make a bracelet with b beads. 1​
Mathematics
2 answers:
Eva8 [605]3 years ago
4 0

Answer:

let the number of beads be b

then cost of bracelet C is = $0.10 +b$0.30

bearhunter [10]3 years ago
3 0

Answer:

Step-by-step explanation:

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Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
Find the surface area of prism
SCORPION-xisa [38]

Answer:

hope it helps mark me brill

Step-by-step explanation:

The general formula for the total surface area of a right prism is T. S. A. =ph+2B where p represents the perimeter of the base, h the height of the prism and B the area of the base.

4 0
3 years ago
Question is show below.
WITCHER [35]

(1/4ab)^-2

Remove negative exponent by rewritten the equation as (4ab)^2

AUse Product rule to get:

4^2a^2b^2

Now raise 4 to the second power to get:

16a^2b^2


The last answer is correct.

7 0
3 years ago
Some help me please i have 9 questions
Lyrx [107]

awnser:

m<3=50

Step-by-step explanation:

seen in the picture if you need help let me know

5 0
3 years ago
Reasoning point F lies on EG and point M lies on EN. If F,E, and M are collinear, what must be true of these rays.
almond37 [142]
This means that all of the points are co-linear. This is because if EG is a segment that contains F, and EN is a segment that contains M, then there can be two different segments. However, for a point F on the first segment and a point M on a second segment be in the same line as an end point of one of the segments, the segments have to be co-linear. They overlap. 
6 0
3 years ago
Read 2 more answers
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