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harina [27]
4 years ago
9

Shawn makes bracelets using stone beads. He buys the beads for $0.30 each. The wire used to make each bracelet costs $0.10. a. W

rite an equation to find the cost (C) to make a bracelet with b beads. 1​
Mathematics
2 answers:
Eva8 [605]4 years ago
4 0

Answer:

let the number of beads be b

then cost of bracelet C is = $0.10 +b$0.30

bearhunter [10]4 years ago
3 0

Answer:

Step-by-step explanation:

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Katt and sanjeev are collecting money for charity. For every £2 that kat collects, sanjeev collects £3. They collect £255 in tot
il63 [147K]

Answer: Kate = £102

Sanjeev = £153

Step-by-step explanation:

From the question, we are informed that for every £2 that kat collects, sanjeev collects £3. This csn be represented in a fraction as:

Kat = 2/5

Sanjeev = 3/5

The amount that each collects will be:

Kat = 2/5 × £255

= 2 × £51

= £102

Sanjeev = 3/5 × £255

= 3 × £51

= £153

6 0
3 years ago
The relation ((6, 8), (7, 10), (7, 12), (8, 16),
Brilliant_brown [7]

Answer:

x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

Step-by-step explanation:

Given the relation

  • {(6, 8), (7, 10), (7, 12), (8, 16), (10, 16)}

We know that a relation is a function that has only one output for any unique input.

As the inputs or x-values of the relations are:

at x = 6, y = 8

at x = 7, y = 10

at x = 7, y = 12

at x = 8, y = 16

at x = 10, y = 16

If we closely observe, we can check that there is a repetition of x values.

i.e. x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

8 0
3 years ago
16^1/2 x 2^-3 what is this
Minchanka [31]

Please find attached photograph for your answer. Please do mark me Brainliest

3 0
3 years ago
Read 2 more answers
-3(8n+10) <br> distributive property
Lerok [7]
-24n - 30, i suggest using math.way before asking a math question aha
6 0
2 years ago
Read 2 more answers
Write a rational function that meets the following criteria:
Sliva [168]
You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2

y = (x - 3)/((x - 1)(x - 3)) + 2
5 0
3 years ago
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