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3 years ago

6

Mike is making a scale model of his favorite car. The actual car is 9 feet long and 3 feet wide. Mike wants his model to be 12 i

nches in length. Which would be the width of his model if he uses the same ratio?

1 answer:

Firlakuza [10]3 years ago

5 0

Answer:

6

Step-by-step explanation:

if you do the ratio 9/12 and 3/x and cross multiply, x=6... I believe

Because

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What is the solution to ln (x2 - 16) = 0?

bogdanovich [222]

ANSWER

$x = \pm \sqrt{17}$
EXPLANATION

The given equation is

$ln( {x}^{2} - 16) = 0$

Take antilogarithm of both sides to base e.

${e}^{ ln( {x}^{2} - 16) } = {e}^{0}$

This will simplify to

${x}^{2} - 16 = 1$

Group like terms to obtain,

${x}^{2} = 1 + 16$

${x}^{2} = 17$

Take square root of both sides to get,

$x = \pm \sqrt{17}$

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3 years ago

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3 years ago

Which of these quadratic expressions is equivalent to

VLD [36.1K]

Answer:

B. (x+8)(x+4)

Step-by-step explanation:

${x}^{2} + 12x + 32 \\ = {x}^{2} + 8x + 4x + 32 \\ = x(x + 8) + 4(x + 8) \\ \red { \bold{ = (x + 8)(x + 4) }}$

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4 years ago

What is the slope the line that passes through the points:<br> (-6, 14), (2, -18)

Vesna [10]

Hey there! I'm happy to help!

Here's how to find the slope given any two points.

Subtract the y values.

14-(-18+-14+18=32

Subtract the x values.

-6-2=-8

And divide those.

32/-8=-4

The slope is -4.

Have a wonderful day! :D

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3 years ago

20 PTS! Please Help!!!! Will Give Brainliest!! This is a Khan Academy Problem!!!

klemol [59]

Using it's concept, the approximate perimeter of pentagon ABCDE is given as follows:

34.4 units.

<h3>What is the perimeter of a figure?</h3>

The perimeter of a figure is given by the sum of the lengths of it's outside dimensions.

In this problem, the vertices are in a coordinate-plane, hence the distances are found using the formula for the distance between two points.

<h3>What is the distance between two points?</h3>

Suppose that we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of segment AB is:

$AB = \sqrt{(6 - 0)^2+(0 - 7)^2} = 9.2$

The length of segment BC is:

$BC = \sqrt{(6 - 3)^2+(0 + 4)^2} = 5$

The length of segment CD is:

$CD = \sqrt{(-3 -3)^2+(-4 + 4)^2} = 6$

The length of segment DE is:

$DE = \sqrt{(-6 + 3)^2+(0 + 4)^2} = 5$

The length of segment EA is:

$EA = \sqrt{(-6 +0)^2+(0 - 7)^2} = 9.2$

Hence the perimeter is:

P = AB + BC + CD + DE + EA = 9.2 + 5 + 6 + 5 + 9.2 = 34.4 units.

More can be learned about the perimeter of a figure at brainly.com/question/18610622

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2 years ago