If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).
sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3
We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)
cos Ф=(-2√2) / 3 this solutions is right.
answer:B. -2 square root 2 /3 (or (-2√2) /3 )
Answer:
Below.
Step-by-step explanation:
3x + 5y = 15
Subtract 3x from both sides:
5y = -3x + 15
Divide through by 5:
y = -3/5 x + 3 <-----------slope-intercept form
Answer:
3.15
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Quite simple when you take out the useless stuff you added in. Its 16
Answer:
1/5
Step-by-step explanation:
