Jordan is cutting a 2 meter by $1\frac{1}{4}$ meter piece of rectangular paper into two pieces along its diagonal. what is the area of each of the pieces?

Answer:

Area of each piece of paper is $1 \frac{1}{4} \ m^2$ .

Solution:

Length of the paper = 2 m

Width of the paper = $1\frac{1}{4}$ m = $\frac{5}{4}$ m

Area of the rectangle = length × width

$$=2\times \frac{5}{4}$

$$= \frac{5}{2} \ m^2$

Diagonal of a rectangle divides it into two equal parts.

Area of each piece = Area of the rectangle ÷ 2

$$=\frac{ \frac{5}{2}}{2}$

$$=\frac{5}{4} \ m^2$

$$=1 \frac{1}{4} \ m^2$

Area of each piece of paper is $1 \frac{1}{4} \ m^2$ .

7 0

3 years ago

Match the inequality to the number line that represents its solution

pav-90 [236]

Tile 1 goes to graph D
Tile 2 goes to graph B
Tile 3 goes to graph A
Tile 4 goes to graph C

Desmos graphing calculator at desmos.com/calculator is a great tool.

8 0

3 years ago

Read 2 more answers

Over what interval is the function in this graph increasing?

brilliants [131]

A function is increasing if it "points upwards".

Think that you have two inputs $x_1$ (think of them as being very close to each other). A function $f$ is increasing if

$f(x_1)$

So, smaller input, smaller output.

So:

In the first segment on the left, the function is decreasing: if you move with little steps rightwards, the output will get smaller and smaller (the function points to the right bottom)
In the second segment, the line is constant (it's horizontal). This means that even if you consider a larger input, the output reimains the same
In the third segment, the function is increasing: if you consider a larger input, the output will be larger as well: the function points to the top right.
In the fourth segment, the function is decreasing again (look at the first bullet point)

So, the function is increasing in the third segment, which is delimited by

$-2\leq x \leq 3$