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ki77a [65]
3 years ago
9

Which number is a perfect cube? A. 8 B. 9 C. 16 D. 25

Mathematics
2 answers:
Tresset [83]3 years ago
5 0
C. 16
2^3 = 16
2x2=4
4x2=8
8x2=16
sattari [20]3 years ago
5 0
The answer is c rn rn rnrnrr en end
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d) none

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How do you algebraically solve for equilibrium using supply and demand equations?
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Answer:

How do you find the equilibrium price with a supply and demand function?

To determine the equilibrium price, do the following.

Set quantity demanded equal to quantity supplied:

Add 50P to both sides of the equation. You get.

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9:45 on Tuesday Questions
Sergio039 [100]

Answer:

  • 95°
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Step-by-step explanation:

<u>Given angles are consecutive interior angles which sum up to 180°</u>

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8 0
3 years ago
Mr bob the baker made 24 pies on monday and 48 on wednesday how many pieces did he made in all
murzikaleks [220]

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8 0
3 years ago
An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i
HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = 750+750*0.05=750(1+0.05)

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

750*(1+0.05)^10=1221.67

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6 0
3 years ago
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