Question

Pls help. Question above

Answer 1

Answer:

$m = \frac{5}{2}$

Step-by-step explanation:

Here are the laws which would be used in this question:

Indices:

• $\sqrt{a} = {a}^{ \frac{1}{2} }$

• $\frac{1}{a} = {a}^{ - 1}$

Logarithm

• $log_{a}( {x}^{n} ) = n log_{a}(x)$

$log_{m}( \sqrt{2} ) + log_{m}(8) + log_{m}( \frac{1}{2} )$

$= log_{m}( {2}^{ \frac{1}{2} } ) + log_{m}( {2}^{3} ) + log_{m}( {2}^{ - 1} )$

$= \frac{1}{2} log_{m}(2) + 3 log_{m}(2) - log_{m}(2)$

$= \frac{5}{2} log_{m}(2)$

Answer 2

What is this type of math called please and what year/grade if you don’t mind me asking so I can be prepared