F = 1.8C + 32
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒
(-10, 14)С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒
(0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒
(10, 50)С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒
(20, 68)
<span>(3x^2+3)(4+x^3)
=</span><span>12x^2 +3x^5 + 12 + 3x^3
= </span>3x^5 + 3x^3 + 12x^2 + 12
He would have four fields. Since the area of 1/2 milex1/2 mile is 1/4, and 1x1 is 1, so 4 fields make up the land.