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pshichka [43]
3 years ago
10

ABCD is a rectangle and BDis one of it's diagonals if ar (ABD)=8cm.Find ar (BCD )

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0
This should be the answer
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A regular triangular pyramid has a base area of 31.5 mm2 and a surface area of
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Answer:

A) 220.5 mm^2

Step-by-step explanation:

<u>Explanation</u>:-

Given A regular triangular pyramid has a base of area is 31.5mm^2

and also given surface area of triangular pyramid is 252 mm ^2

by using formula

surface area of  regular triangular pyramid = base of area + half of lateral surface.

surface area = area of the pyramid X \frac{1}{2} lateral surface

252 = 31.5 + \frac{1}{2} lateral surface

252-31.5= \frac{1}{2} lateral surface

220.5 = lateral area of triangular pyramid

lateral area of triangular pyramid = 220.5 mm^2

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Help me with these questions
egoroff_w [7]
For number 6 it's 30 x 45
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