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RSB [31]
3 years ago
5

Which graph could represent the following story? Trent walked from the cafeteria to his math class. After class, he walked back

to the cafeteria and stopped to get a beverage from a vending machine on the way.
A) Image 1 (1st Image)
B) Image 2 (2nd Image)
C) Image 3 (3rd Image)
D) Image 4 (4th Image)

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

D) Image 4 (4th Image)

Step-by-step explanation:

The maths class is away from the cafeteria so the line inclines upwards. The line then stays flat indicating the time spent in the same spot at his maths class. Then he starts heading back to the cafeteria and the line inclines downward. He then stops along the way for a drink which indicates the second flat line where he spent time in the same spot. Finally, the line inclines all the way down towards the bottom showing that he is back at the cafeteria.

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A rock is thrown upward from a bridge that is 57 feet above a road. The rock reaches its maximum height above the road 0.76 seco
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answer:

f(t) = -9.9788169(t -0.76)^2 +57

Step-by-step explanation:

On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the  number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).

now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is f(x)= a(x-p)^2 +q  , where (p,q) is the turning point. now we substitute the turning point

f(t) = a(t-0.76)^2 + 57, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.

0 = a(3.15 - 0.76)^2 + 57

-57 =a(2.39)^2  

-57 = a(5.7121)

-57/5.7121 =a

-9.9788169 = a      then we substitute a to get the quadratic equation therefore f is

f(t) = -9.9788169(t-0.76)^2 +57

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