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Nimfa-mama [501]
3 years ago
15

In this reaction, how many miles of CO2 would be produced when methane (CH4) fully reacts with 6 moles of O2? CH4 + 2O2 - 2H2O +

CO2
Physics
2 answers:
kodGreya [7K]3 years ago
8 0

Answer: 3

Explanation:

Sindrei [870]3 years ago
4 0

Answer:

3 moles

Explanation:

Ratio of O2 to CO2 = 2 : 1 = 6 : 3

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Scientists are studying a group of living cells under a microscope. They write down notes about the size, shape, and color of th
Lilit [14]

Answer:

D

Explanation:

descriptive, because scientists are writing down the observations but not making comparisons.  

3 0
3 years ago
What is the acceleration of a proton moving with a speed of 7.7 m/s at right angles to a magnetic field of 1.9 T
iris [78.8K]

Answer:

The acceleration of the proton is 1.403 x 10⁹ m/s²

Explanation:

Given;

speed of proton, v = 7.7 m/s

magnitude of magnetic field, B = 1.9 T

Magnetic force of moving proton is given by;

F = qvBsinθ

Centripetal force on the moving proton is given by;

F = m(\frac{v^2}{r})\\\\F = m(a_c) \\\\a_c \ is \ the \ centripetal \ acceleration

qvBsin\theta = ma_c\\\\ac = \frac{qvBsin(90)}{m}

where;

q is charge of the proton = 1.602 x 10⁻¹⁹ C

m is mass of proton = 1.67 x 10⁻²⁷ kg

ac = \frac{(1.602*10^{-19})(7.7)(1.9)sin(90)}{1.67*10^{-27}}\\\\a_c = 1.403*10^{9} \ m/s^2

Therefore, the acceleration of the proton is 1.403 x 10⁹ m/s²

3 0
3 years ago
Imagine that person B is more massive than person A in the picture above. 3 points
mote1985 [20]

Answer:bight

Explanation:

4 0
3 years ago
Extra CreditA particle is directed along the axis of the instrument in the gure. Aparallel plate capacitor sets up an electric e
kvv77 [185]

This question is incomplete, the complete question is;

A particle is directed along the axis of the instrument in the figure below. A parallel plate capacitor sets up an electric field E, which is oriented perpendicular to a uniform magnetic field B. If the plates are separated by d = 2.0 mm and the value of the magnetic field is B = 0.60T.

Calculate the potential difference, between the capacitor plates, required to allow a particle with speed v = 5.0 × 10⁵ m/s to pass straight through without deflection.

<em>Hint </em>: ΔV = Ed <em> </em>

Answer:

the required potential difference, between the capacitor plates is 600 V

Explanation:

Given the data in the question;

B = 0.60 T

d = 2.0 mm = 0.002 m

v = 5.0 × 10⁵ m/s.

since particle pass straight through without deflection.

F_{net = 0

so, F_E = F_B

qE = qvB

divide both sides by q

E = vB

we substitute

E = (5.0 × 10⁵) × 0.6

E = 300000 N/C

given that; potential difference ΔV = Ed

we substitute

ΔV = 300000 × 0.002

ΔV = 600 V

Therefore, the required potential difference, between the capacitor plates is 600 V

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3 years ago
What is the definition of physical activity?
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3 years ago
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