Answer:
Distance covered by B is 4 times distance covered by A
Explanation:
For an object in free fall starting from rest, the distance covered by the object in a time t is

where
s is the distance covered
g is the acceleration due to gravity
t is the time elapsed
In this problem:
- Object A falls through a distance
during a time t, so the distance covered by object A is

- Object B falls through a distance
during a time 2t, so the distance covered by object B is

So, the distance covered by object B is 4 times the distance covered by object A.
Frictional force = vertical force x coeff of friction = 590N x 0.045 = 26.55N
Mass of boy and sled = 590N / g = 590N / 9.8m/s^2 = 60.20 kg
Deceleration due to friction = 26.55N / 60.20kg = 0.44 m/s^2.
For constant acceleration we have:
v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and ti is time. In this case v = 0, u = 5.9 m/s, a = -0.44 m/s^2. So we have
0 = 5.9 - 0.44t
which gives t = 5.9 / 0.44 = 13.409 s.
Distance traveled in this time d = ut + 0.5at^2 = 5.9 x 13.409 - 0.5 x 0.44 x 13.409^2 = 39.56 m
<span>Answer: </span>40 meters
Answer:
The answer is "4".
Explanation:
The luminaire would be recessed inside a wall, so that, dependent on the surface mountings, its top-level is flush with the ceiling. It is the hanging under the primary structural, in which the drop was an area of the above falling ceiling, that referred to its full space, because it will be generally used for the HVAC air return and the total space is also used to obfuscate piping, cabling, and ducts, that's why the middle-to-middle spacing of curved lighting systems would have to be in incremental increases of 4 ft.
44/5 seconds to g<span>o from a complete stop to 44 km/h</span>