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iVinArrow [24]
3 years ago
11

Two forces that act on very small distances (smaller than you can see ) are

Physics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
There are three fundamental forces that act at a distance. They are gravitational, electromagnetic and nuclear forces.
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Mountain Ecosystems Assignment Answer each question below in complete sentences.1) Identify a predator from an Ethiopian Highlan
Marta_Voda [28]

An example of a a predator in the Ethiopian Highlands ecosystem is the

Wolf.The wolf is a carnivore which acts as a predator to other smaller

animals in the ecosystem.

<h3>What is a Prey?</h3>

Preys are mostly smaller animals in which the predators feed on for food.

They are usually herbivores and primary consumers in the ecosystem.

Examples of Preys include:

  • Rodents
  • Deer
  • Bison etc.

Read more about Feeding relationship here brainly.com/question/9852437

8 0
2 years ago
If a 340 g ball has 2.4 J of kinetic energy, what is it's velocity?
Leno4ka [110]

Answer:

Explanation:

i really dont know im a 4th grader

6 0
3 years ago
Read 2 more answers
Eli's gross income as a painter is $30,000 per year, which places him in the 15% approximate tax bracket. How much does he pay i
Umnica [9.8K]

Answer: $4,500

Explanation: 1% of $30,000 would be $300. If you multiply that by 15, you get $4,500, so 15% of 30,000 is 4,500.

3 0
3 years ago
A motorcycle traveling at 25 m/s accelerates ya a rate of 7.0 m/s2 for 6.0 seconds. What is the final velocity of the motorcycle
frutty [35]

First write down all your known variables:

vi = 25m/s

a = 7.0m/s^2

t = 6.0s

vf = ?

Then choose the kinematic equation that relates all the variables and solve for the unknown variable:

vf = vi + at

vf = (25) + (7.0)(6.0)

vf = 67m/s

The final velocity of the motorcycle is 67m/s.

4 0
4 years ago
Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull
bearhunter [10]

Answer:

strain = 1.4 \times 10^{-3}

Explanation:

As we know by the formula of elasticity that

E = \frac{stress}{strain}

now we have

E = 110 GPA

E = 110 \times 10^9 Pa

Area = 15.2 mm x 19.1 mm

A = 290.3 \times 10^{-6}

now we also know that force is given as

F = 44500 N

here we have

stress = Force / Area

stress = \frac{44500}{290.3 \times 10^{-6}}

stress = 1.53 \times 10^8 N/m^2

now from above formula we have

strain = \frac{stress}{E}

strain = \frac{1.53 \times 10^8}{110 \times 10^9}

strain = 1.4 \times 10^{-3}

7 0
3 years ago
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