3 years ago

Two forces that act on very small distances (smaller than you can see ) are

Physics

1 answer:

BlackZzzverrR [31]3 years ago

7 0

There are three fundamental forces that act at a distance. They are gravitational, electromagnetic and nuclear forces.

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Mountain Ecosystems Assignment Answer each question below in complete sentences.1) Identify a predator from an Ethiopian Highlan

Marta_Voda [28]

An example of a a predator in the Ethiopian Highlands ecosystem is the

Wolf.The wolf is a carnivore which acts as a predator to other smaller

animals in the ecosystem.

Preys are mostly smaller animals in which the predators feed on for food.

They are usually herbivores and primary consumers in the ecosystem.

Examples of Preys include:

Rodents

Deer

Bison etc.

Read more about Feeding relationship here brainly.com/question/9852437

8 0

2 years ago

If a 340 g ball has 2.4 J of kinetic energy, what is it's velocity?

Leno4ka [110]

Answer:

Explanation:

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6 0

3 years ago

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Eli's gross income as a painter is $30,000 per year, which places him in the 15% approximate tax bracket. How much does he pay i

Umnica [9.8K]

Answer: $4,500

Explanation: 1% of $30,000 would be $300. If you multiply that by 15, you get $4,500, so 15% of 30,000 is 4,500.

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3 years ago

A motorcycle traveling at 25 m/s accelerates ya a rate of 7.0 m/s2 for 6.0 seconds. What is the final velocity of the motorcycle

frutty [35]

First write down all your known variables:

vi = 25m/s

a = 7.0m/s^2

t = 6.0s

vf = ?

Then choose the kinematic equation that relates all the variables and solve for the unknown variable:

vf = vi + at

vf = (25) + (7.0)(6.0)

vf = 67m/s

The final velocity of the motorcycle is 67m/s.

4 0

4 years ago

Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull

bearhunter [10]

Answer:

$strain = 1.4 \times 10^{-3}$

Explanation:

As we know by the formula of elasticity that

$E = \frac{stress}{strain}$

now we have

$E = 110 GPA$

$E = 110 \times 10^9 Pa$

Area = 15.2 mm x 19.1 mm

$A = 290.3 \times 10^{-6}$

now we also know that force is given as

$F = 44500 N$

here we have

stress = Force / Area

$stress = \frac{44500}{290.3 \times 10^{-6}}$

$stress = 1.53 \times 10^8 N/m^2$

now from above formula we have

$strain = \frac{stress}{E}$

$strain = \frac{1.53 \times 10^8}{110 \times 10^9}$

$strain = 1.4 \times 10^{-3}$

7 0

3 years ago