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lutik1710 [3]
3 years ago
13

I need help on my math question so whats c?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

c = -25

Step-by-step explanation:

Multiply the denominator by -7 on both sides, you would then get the equation c + 32 = 7 in which the -7 on the left side cancels out.  Subtract 32 on both sides to get the c value which is -25.

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Seattle-Pipes Co. produces pipes to be supplied to a Seattle utility company. The requirement of the utility company is that the
Goshia [24]

Answer:

Step-by-step explanation:

Hello!

The study variable is

X: Pipe length.

It is known that this variable has a normal distribution and that the distribution parameter varies depending on the process used to manufacture the pipes.

Process A: μ= 200cm δ= 0.5cm

Process B: μ=201cm δ= 1cm

Process C: μ=202cm δ= 1.5cm

Pipes with a length of 200cm or more will be accepted by the utility company (X≥200), but pipes with less than 200cm length will be rejected (X<200)

a. Using Process C, you need to calculate the probability that the pipe will be rejected, symbolically:

P(X<200)

Using the distribution data of process C you have to standardize the value:

P(Z<(200-202)/1.5)= P(Z<-1.33)= 0.09176

b. The requirements change, accepting any pipe between 199 and 202, you have to calculate the probabilities of the pipes being between those lengths using the three process:

Process A:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-200)/0.5)) - P(Z≤(199-200)/0.5))

P(Z≤4) - P(Z≤-2) = 1 - 0.02275 = 0.97725

The probability of the pipe being rejected is 0.02275

Process B:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-201)/1)) - P(Z≤(199-201)/1))

P(Z≤1) - P(Z≤-2) = 0.84134 - 0.02275 = 0.81859

The probability of the pipe being rejected is 1-0.81859= 0.18141

Process C:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-202)/1.5)) - P(Z≤(199-202)/1.5))

P(Z≤0) - P(Z≤-2) = 0.5 - 0.02275 = 0.47725

The probability of the pipe being rejected is 1-0.47725= 0.52275

The pipes manufactured using process A has fewer chances of being rejected.

c.

Process A costs $140

P(X≥200)= 1 - P(X<200)= 1 - P(Z<0)= 1 - 0.5= 0.5

Process B costs $160

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1)= 1 - 0.15866= 0.84134

Process C costs $177

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1.33)= 1 - 0.09176= 0.90824

If they where to make 100 pipes:

Using process A: 100*0.5= 50 pipes will be accepted, so they'll win 50*($200-$140)= $3000

Using process B: 100*0.84134= 84.134≅ 84 pipes will beaccepted, so they'll win 84*($200-$160)= $3360

Using the process C: 100*0.90824= 80.824≅ 90 pipes will be accepted, so they'll win 90*($200-$177)= $2070

As you can see, using process B will maximize the profits.

I hope it helps!

6 0
4 years ago
Evaluate 2x^2 − 5y / 3x − y when x = 2 and y = -4
kipiarov [429]
It is -7/2 when the variables are substituted
3 0
3 years ago
Read 2 more answers
HELP DUE IN 10 MINUTES!!!!
Irina-Kira [14]

Answer:

x=7

y=0

Step-by-step explanation:

you can solve by using subsitution.

(2*7)-(9*0)=14

7=(-6*0)+7

Pls mark brainliest. thx have a nice day.

5 0
2 years ago
Heather had to collect insects for her biology project. She was able to collect 225 total insects. She collected 8 times as many
GREYUIT [131]

200 flying insects she catch for her project .

<u>Step-by-step explanation:</u>

We have , Heather had to collect insects for her biology project. She was able to collect 225 total insects. She collected 8 times as many insects that could fly as insects that couldn't fly. That means insects ratio of non-fly to fly is 1:8 .

There are a total of 225 insects , and for every one non fly insect there are 8 fly insects  , Let x be the number of insects that can't fly so:

x + 8x = 225

⇒ x + 8x = 225

⇒ 9x = 225

⇒ \frac{9}{9}x = \frac{225}{9}

⇒ x = \frac{225}{9}

⇒ x = 25

So , Number of fly insects = 8x = 8(25) = 200 . ∴ 200 flying insects she catch for her project .

5 0
3 years ago
Given the vectors w = &lt;-5, 3&gt; and z = &lt;1, 4&gt;, find the results of the vector subtractions. -w − z = z − w = w − z =
Elodia [21]

Answer:

Concept: Linear Algebra

  1. Given two linearly independent vectors w and z
  2. We want -w-z
  3. Hence apply a negative gradient to w
  4. w=-<-5,3> =<5,-3>
  5. So <5,-3>-<1,4> = (<5-1>,<-3-4>)
  6. The answer is <4,-7>
4 0
3 years ago
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