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3 years ago

Help on this problem please!!

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

5 0

Answer:

points (8, 0) and (3, 0)

Step-by-step explanation:

Here we're being asked to find the roots of this quadratic equation.

Set f(x) = 3(x² - 11x + 24 = 0.

This factors into f(x) = 3(x - 8)(x - 3) = 0.

Then x - 8 = 0 and x - 3 = 0, yielding x = 8 and x = 3. These correspond to the points (8, 0) and (3, 0).

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ARITHMETIC AND ALGEBRA REVIEW

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42 inches of wire will cost 168 cents

Look at the pic to see how to set up the proportion.

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3 years ago

How do you illustrate quadratic equation in one varible?

kvasek [131]

Answer:

A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable. One absolute rule is that the first constant "a" cannot be a zero.

Step-by-step explanation:

6 0

3 years ago

Anyone can help me solve this equation using cross multiplying

Natali5045456 [20]

9514 1404 393

Answer:

x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)$

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

$3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}$

_____

Comment on "cross multiply"

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes what the result looks like. It doesn't adequately describe how you get there. The one and only rule in solving Algebra problems is "whatever is done to one side of the equation must also be done to the other side of the equation." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "multiply by the product of the denominators and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}$

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3 years ago

Almonds cost $5 per pound. Cashews cost $2 per pound. Matt purchased a container of almonds and cashews that sells for $3 per po

kvv77 [185]

Answer:

Step-by-step explan

8 0

3 years ago

Can any one please help me in this the teacher did not explain this it have to be in the lowest term also no decimal answer than

Zinaida [17]

Answer:

Step-by-step explanation:

$A . -5+3x =-41\\3x=-41+5\\3x = -36\\\frac{3x}{3} =\frac{-36}{3} \\x = -12\\\\\\\\\\B. 7x-4=-2x+11\\Collect-like-terms\\7x+2x=11+4\\9x=15\\\frac{9x}{9} =\frac{15}{9} \\\\x = \frac{5}{3} \\\\C. \frac{-4x}{5} =8\\Cross-multiply\\-4x=40\\\frac{-4x}{4} =\frac{40}{-4} \\x = -10\\\\D. \frac{x}{3} -\frac{1}{2} =\frac{1}{4} \\\frac{x}{3} =1/4+1/2\\\frac{x}{3} = \frac{3}{4} \\Cross-multiply\\4x =9\\4x/4 =9/4\\x = 9/4\\$

$E . -4(6x+1)+3 =11+2(x+2)\\-24x-4+3=11+2x+4\\Collect-like-terms\\-24x-2x=11+4+4-3\\-26x =16\\\frac{-26x}{-26} =\frac{16}{-26}\\ x = -\frac{8}{13}$

7 0

3 years ago