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juin [17]
3 years ago
9

The floor of a hall has an area of 48 dm.The floor is to be tiled by triangular tiles.of sides 20 cm,30 cm and 40 cm. Find the t

otal cost of tiles if cost of each tile is Rs.200.
Mathematics
1 answer:
vovangra [49]3 years ago
7 0
The triangle is an obtuse triangle. No sides are equal.
convert cm to dm

1 dm = 10 cm

side a: 20 cm ⇒ 20cm * 1dm/10cm = 20dm/10 = 2 dm
side b: 30 cm ⇒ 30cm * 1dm/10cm = 30dm/10 = 3 dm
side c: 40 cm ⇒ 40cm * 1dm/10cm = 40dm/10 = 4 dm

We need to get the area of a triangle, but first we need to solve for its height using Heron's formula

s = (a+b+c)/2 = (2+3+4)/2 = 9/2 = 4.5
<span>Area = </span>√<span>(s(s-a)(s-b)(s-c)
</span>h3/2 = √4.5(4.5-2)(4.5-3)(4.5-4)
h3/2 = √4.5(2.5)(1.5)(0.5)
h3/2 = √8.44
h3/2 = 2.91
h = (2.91*2)/3
h = 1.94

A = hb/2 = (1.94*3)/2 = 5.82/2 = 2.91 dm²

48 dm² / 2.91dm² = 16.5 or 17 tiles needed

17 x Rs200 = Rs3,400 is the total cost
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Answer:

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Step-by-step explanation:

17x - 12 = 114 + 3x

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vladimir2022 [97]

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the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

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substitute in the formula

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AB=\sqrt{(0)^{2}+(4)^{2}}

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step 2

Find the distance BC

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substitute in the formula

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step 3

Find the distance AC

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substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

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