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Stells [14]
2 years ago
7

PLEASE HELP f(x) = x2. What is g(x)?

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
4 0

Answer: Choice C.  g(x) = (3x)^2

To confirm this, plug in x = 1 and you'll find that:

g(x) = (3x)^2

g(1) = (3*1)^2

g(1) = (3)^2

g(1) = 3*3

g(1) = 9

Showing that (1,9) is on the red g(x) curve.

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tigry1 [53]

Answer:

17

Step-by-step explanation:

you said that in the problem lol

5 0
2 years ago
Read 2 more answers
Convert the decimals to fractions in the simplest fractions.<br> Show your work<br> 10.6=<br> 5.05=
professor190 [17]

Answer: 53/5, 101/20

Step-by-step explanation:

10.6 is =  106/10. Then divide both numerator and denominator by 2. Then it equals 53/5.

5.05 = 505/100. Then divide both numerator and denominator by 5. This will equal 101/20.

5 0
2 years ago
THIS IS IMPORTANT!!What is the apparent solution to the system of equations?
Ann [662]
Make each equation equal to each other, then solve for x.
-x+2=4x+7
-x-4x=7-2
-5x=5
X=-1
Sub x into one if the y formulas to find y
Y=4x+7
Y=4(-1)+7
Y=-4+7
Y=3
See my picture for how to graph the points.
Hope this helps!

8 0
3 years ago
the Royal fruit company produces two types of fruit drinks. The first type is 20% pure fruit juice, and the second type is a 45%
AlexFokin [52]

We know that 20% of the first type of juice is pure fruit juice and 45% of second type of juice is pure fruit juice.

Now we have to make 30 pints of a mixture that is 35% pure.

Let x be the number of pints of first type of juice and y be the number of pints of second type of juice.

So, x+y=30 (Equation 1)

Since, 20% of x + 45% of y = 35.3% of 30

\frac{x}{5}+\frac{9y}{20}=10.5 (Equation 2)

Solving equations 1 and 2,

we get y=18 and x=12.

So, 12 pints of first type of juice and 18 pints of second type of juice are used.

6 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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