Answer:
Option (1)
Step-by-step explanation:
By the inscribed angle theorem inside a circle,
"Measure of an inscribed angle is half the measure of the intercepted arc"
[m(arc AB)] = m(∠ABC)
m(arc AB) = 2[m(∠ABC)]
x = 2(41°)
x = 82°
Option (1) is the correct option.
Note: a radioactive decay constant is always negative.
time = [natural log(ending amount / beginning amount)] / k
time = ln (20 / 24) / -.00011
time = ln (5/6) / -.00011
time = -.018232155683 / -.00011
time =
<span>
<span>
<span>
165.7468698455
</span>
</span>
</span>
time =
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<span>
<span>
165.75 years
</span></span></span>
Answer:
133.33g
Step-by-step explanation:
Let the:
Mass of 1.2g/cm³ of liquid = x
Mass of 1.8g/cm³ of liquid = y
From our Question above, our system of equations is given as:
x + y = 400........ Equation 1
x = 400 - y
1.2 × x + 1.8 × y = 1.6 × 400
1.2x + 1.8y = 640..... Equation 2
We substitute, 400 - y for x in Equation 2
1.2(400 - y) + 1.8y = 640
480 - 1.2y + 1.8y = 640
- 1.2y + 1.8y = 640 - 480
0.6y = 160
y = 160/0.6y
y = 266.67 g
Solving for x
x = 400 - y
x = 400 - 266.67g
x = 133.33g
Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g
This = P(message is from Steven) = number of messages from steven / total number of messages from previous night
= 5 / (4+11+5+9+24) = 5/53 Answer
The solution would be like this for this specific problem:
Volume of a cylinder = pi * r^2 * h
Volume of a cone = 1/3 * pi * r^2 * h
Total Height = 47
Height of the cone = 12
Height of the cylinder = 35
If the top half is filled with sand, then:
volume (sand) = pi * 4^2 * 36
volume (cone) = 1/3 * pi * 4^2 * 12
Total volume = 1960.353816 cubic millimeters
353816 / (10 * pi) = 62.4 seconds.
It will take 62.4 seconds until all of the sand has dripped to the bottom of the hourglass.
