Answer:
u * v = 39 ⇒ 2nd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- u and v are two vectors
- u * v means the scalar product of the two vectors
- The scalar product is a way of multiplying vectors
- The result of a scalar product is always a number not a vector
- Ex: If u = ai + bj ⇒ <a , b> and v = ci + dj ⇒ <c , d> then the scalar
product of them is ac + bd where ac + bd is a number
* Lets solve the problem
∵ Vector u = 13j ⇒ <0 , 13>
∵ Vector v = i + 3j ⇒ <1 , 3>
- Lets find the scalar product
∴ u * v = (0)(1) + (13)(3)
∴ u * v = 0 + 39
∴ u * v = 39
Answer:
The answer is c
Step-by-step explanation:
Answer:
You earned an A.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 79, \sigma = 6](https://tex.z-dn.net/?f=%5Cmu%20%3D%2079%2C%20%5Csigma%20%3D%206)
The top 15% of all scores have been designated As.
This means that if Z for the score has a pvalue of 1-0.15 = 0.85 or higher, the score is designated as A.
Your score is 89. Did you earn an A?
We have to find the pvalue of Z when X = 89. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{89 - 79}{6}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B89%20-%2079%7D%7B6%7D)
![Z = 1.67](https://tex.z-dn.net/?f=Z%20%3D%201.67)
has a pvalue of 0.9525. So yes, you earned an A.
Commutative Property of Addition
I think it’s the third option