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3 years ago

Find the area of polygon ABCDE with vertices A(0, 0), B(0, 4), C(8, 8), D(14, 0), and F(9, −2).

Mathematics

1 answer:

sammy [17]3 years ago

7 0

It is C 108 square units

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Translate this sentence into an equation

Yuki888 [10]

I'm pretty sure the answer is d • 3 = 48

3 0

3 years ago

Equation of the line (-6,5) and (8,14) in standard form

blsea [12.9K]

Answer:

$\huge\boxed{9x-14y=-70}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (-6, 5) and (8, 14).

Substitute:

$m=\dfrac{14-5}{8-(-6)}=\dfrac{9}{14}\\\\y-5=\dfrac{9}{14}(x-(-6))\\\\y-5=\dfrac{9}{14}(x+6)$

Thew standard form of an equation of a line:

$Ax+By=C$

transform:

$y-5=\dfrac{9}{14}(x+6)\qquad|\text{multiply both sides by 14}\\\\14y-14\cdot5=14\!\!\!\!\!\diagup^1\cdot\dfrac{9}{14\!\!\!\!\!\diagup_1}(x+6)\\\\14y-70=9(x+6)\\\\14y-70=9x+54\qquad|\text{subtract}\ 9x\ \text{from both sides}\\\\-9x+14y-70=54\qquad|\text{add 70 to both sides}\\\\-9x+14y=70\qquad|\text{change the signs}\\\\9x-14y=-70$

4 0

4 years ago

3x+6/x^2-x-6+2x/x^2+x-12

Tanzania [10]

$\dfrac{3x+6}{x^2-x-6} + \dfrac{2x}{x^2+x-12}$

$= \dfrac{3(x+2)}{(x + 2)(x - 3)} + \dfrac{2x}{ (x - 3)(x + 4)}$

$= \dfrac{3}{(x - 3)} + \dfrac{2x}{ (x -3)(x + 4)}$

$= \dfrac{3(x+4)}{(x - 3)(x + 4)} + \dfrac{2x}{ (x -3 )(x + 4)}$

$= \dfrac{3(x+4) + 2x }{(x - 3)(x + 4)}$

$= \dfrac{3x+12 + 2x }{(x - 3)(x + 4)}$

$= \dfrac{5x+12}{(x - 3)(x + 4)}$

6 0

3 years ago

If breadth of a rectangle is 19m and perimeter is 80m, find the length of the rectangle.

soldi70 [24.7K]

Answer: 21

Step-by-step explanation:

since 19 is the breadth and the perimeter is 80m, so 19*2=38 and 80-38= 42 so 42/2=21. The answer is 21

3 0

3 years ago

Determine the number of real solutions of -2x2 + 5x - 3 = 0.

andrew11 [14]

-2x^2 + 5x -3 =0

Find the discriminate:

In the given formula a = -2, b = 5 and c = -3

The discriminate is found using the formula b^2 - 4(ac)

Replace the letters with their values:

5^2 - 4(-2*-3)

25 - 4*6

25-24 = 1

When the discriminate is greater than or equal to 0, there are two real solutions.

The answer is c) 2

4 0

3 years ago