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andreyandreev [35.5K]
3 years ago
5

Find the area of polygon ABCDE with vertices A(0, 0), B(0, 4), C(8, 8), D(14, 0), and F(9, −2).

Mathematics
1 answer:
sammy [17]3 years ago
7 0
It is C 108 square units
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Step-by-step explanation:

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I need help with these three
Ludmilka [50]
A. The relationship of <7 and <8 are that they are vertical angles, and are congruent.

B. Since vertical angles are congruent, you can form an equation where the two measurements equal each other. 

C. 5y-29=3y+19       then plug y into your equation: 5*24-29=91
    2y=48                   and so: <7 = 180-91=89 (and since <8 is congruent)
    y=24                     <8 also equals 89

Your second problem: 
complementary are two angles that add up to 90 degrees.
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2x+x=90
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x=30       so: <B=30 degrees, <A=60 degrees

Your third problem:
1. Since A and B are parallel, angle 3x+7 and angle 4x+5 are same-sided exterior angles. That means that they both add up to 180 degrees. So if you should add the two and make it equal 180
2. 3x+7+4x+5=180
    7x+12=180
    7x=168
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3. <6 is a corresponding angle with angle 3x+7, meaning that they are congruent. So plug x into 3x+7: 3*24+7=79 and since <6 is congruent to 3x+7, <6=79 degrees
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