Answer:

Step-by-step explanation:
<u>Fundamental Theorem of Calculus</u>

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.
Given indefinite integral:


If the terms are multiplied by constants, take them outside the integral:

Multiply by the conjugate of 1 - sin(6x) :






Expand:






![\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}](https://tex.z-dn.net/?f=%5Cimplies%2012%20%5Cleft%5B%5Cdfrac%7B1%7D%7B6%7D%20%5Ctan%20%286x%29%2B%5Cdfrac%7B1%7D%7B6%7D%20%5Csec%20%286x%29%20%5Cright%5D%2B%5Ctext%7BC%7D)
Simplify:


Learn more about indefinite integration here:
brainly.com/question/27805589
brainly.com/question/28155016
Answer:
−9+16
Step-by-step explanation:
1. 10−3(3−2)
10−9+6
2. Add the numbers
3. Rearrange terms
INCREMENT
430-400=30
PERCENTAGE
(30/400)*100
(30/40)*100
300/40=
7.5% is your final answer
I hope I could help
Answer:
A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)
B) Lakshmi is the tallest, 1.56m tall
Step-by-step explanation:
Rahul- 1.54m
Akash- 1500mm
Meera- 152cm
Lakshmi- 1560mm
Let's start by converting all the measurements to meters.
Rahul is already in meters, so he can just stay the same.
1500mm = 1.5m
152cm = 1.52m
1560mm = 1.56m
So our new measurements are:
Rahul- 1.54m
Akash- 1.5m
Meera= 1.52m
Lakshmi= 1.56m
We can now make our conclusions.
A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)
B) Lakshmi is the tallest, 1.56m tall
Answer:
Hours slept = 6 hours
Hours awake = 18 hours
Step-by-step explanation:
Sasha got 1 hour of sleep for every 3 hours she was awake.
So,
<u>This means:</u>
Slept : Awake = 1 : 3
Total hours in a day = 24 hours
<u>Let </u>
Hours slept = 1x and hours awake = 3x
<u>Hence,</u>
1x + 3x = 24 hours
4x = 24
Divide both sides by 4
x = 24 / 4
x = 6
<u>So,</u>
Hours slept = 1(6) = 6 hours
Hours awake = 3(6) = 18 hours
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>