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Vikki [24]
3 years ago
11

Someone please help me!!! I will mark brainlist!

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0
It would be (-5, 15) or b.
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The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [600]
\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
3 years ago
Read 2 more answers
Find the future value of $3633.49 invested for 2 years at 4% compounded monthly? ​
SSSSS [86.1K]

Answer:

$290.68

Step-by-step explanation:

$3633.49 times 2 times 4% = $290.68

3 0
3 years ago
Anyone please help me anyone
NARA [144]

Answer:

The third answer: x+1

Step-by-step explanation:

Remember when writing roots, the signs are backwards. This is because you start with (x-__) and fill in the root.

So for x = -1, it'll be written as (x+1) [aka (x- -1)]

For x = -3, it'll be written as (x+3)

For x = 5, it'll be written as (x-5)

The only answer that is one of these is the the third answer

7 0
2 years ago
Squad root of 130 by using the Babylonian method. Let 11.5 be initial.
tangare [24]


The Babylonian method for approximating square roots is the recursive method given by:

Given:

x0≈k−−√
x
0
≈
k


Then:

xn+1=x2n+k2xn
x
n
+
1
=
x
n
2
+
k
2
x
n


where k
k
is the number for which we are approximating the square root.

So, armed with this formula, let's now answer the given questions:

1.) Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.

We will use 15 digits of precision here since it is not stated how many iterations to carry out:

x0=11.5
x
0
=
11.5


x1≈11.4021739130435
x
1
≈
11.4021739130435


x2≈11.4017542587143
x
2
≈
11.4017542587143


x3≈11.4017542509914
x
3
≈
11.4017542509914


x4≈11.4017542509914
x
4
≈
11.4017542509914


Thus, with 15 digits of accuracy, we may state:

130−−−√≈11.4017542509914
130
≈
11.4017542509914


2.) Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?

The next result here is approximately:

x1=10.72622+1152⋅10.7262≈10.7238055620816
x
1
=
10.7262
2
+
115
2
⋅
10.7262
≈
10.7238055620816



3.) Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?

The next result here is:

x1=7.82+582⋅7.8=7.6179487¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
x
1
=
7.8
2
+
58
2
⋅
7.8
=
7.6
179487
¯


4.) If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?

The next result here is:

x1=82+752⋅8=8.6875
x
1
=
8
2
+
75
2
⋅
8
=
8.6875
6 0
3 years ago
If mary had 4.55$ and john had 15.18$ how much money do they have all together​
Ilia_Sergeevich [38]
Together, Mary and John had $19.73
8 0
3 years ago
Read 2 more answers
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