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Korolek [52]
3 years ago
12

Find the area of an equilateral triangle with side 8

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0
Hello! I believe the answer is 27.71.


I hope this helps!
vfiekz [6]3 years ago
3 0
27.7 is the answer just took the test
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(3x -1) + (2x+1) (x)
almond37 [142]
The answer is X = 6

Because 3 times 2 x is 6x ... then -1 plus 1 is 0 so it levels out and x is 6
3 0
3 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
3 years ago
What is the value of x?
vredina [299]

Answer:

<em>x=</em><em>3</em><em>0</em><em>°</em>

hopefully this answer can help you to answer the next question

6 0
3 years ago
[ls help me on this
Lady bird [3.3K]
Help you on what?i do not see anything
4 0
4 years ago
Explain how to evaluate simplify and convert to radical form (x^3/8)^3/4
Vaselesa [24]

Answer:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

Step-by-step explanation:

Given

(x^\frac{3}{8})^\frac{3}{4}

Required

Convert to radical form

(x^\frac{3}{8})^\frac{3}{4}

Evaluate the exponents

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{3*3}{8*4}

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{9}{32}

Split the exponent

(x^\frac{3}{8})^\frac{3}{4} = (x^9)^\frac{1}{32}

Apply the following law of indices

(x^a)^\frac{1}{b} = \sqrt[b]{x^a}

So, we have:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

3 0
3 years ago
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