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iris [78.8K]
3 years ago
8

Between which two numbers does the square root of 131 lies?

Mathematics
2 answers:
laiz [17]3 years ago
7 0
11 and 12 because sqrt131 is about 11.46
Gelneren [198K]3 years ago
3 0

Answer:

11 and 12

Step-by-step explanation:

this is because the square root of 121 is 11 and the square root of 144 is 12 so the answer will lie between 11 and 12

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Help? <br> The circumference of a circle is 25 cm. Find the length of the radius
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It’s around 3.979 cm
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3 years ago
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The total cost of 5 pencils and 1 protractor which costs $3.00 is twice the total cost of 3 pencils and 2 erasers that each cost
Stolb23 [73]

Answer:1.73$ per pencile

Step-by-step explanation:

4 0
2 years ago
An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
The length of a rectangle is 4cm more than three times its width. If the
kotegsom [21]

Answer:

22cm by 6cm

Step-by-step explanation:

Width = x

Length = 3x + 4

x + x + 3x + 3x + 4 + 4 = 8x + 8

Perimeter = (8x + 8) cm

56 - 8 = 48cm

48/8 = 6

6 = x

Width = 6cm

Length = 22cm

Please mark as Brainliest, thank you!

5 0
3 years ago
A factor in determining the usefulness of an examination as a measure of demonstrated ability is the amount of spread that occur
Natali [406]

Answer: . a. 36.08 to 78.80

Step-by-step explanation:

 The confidence interval for population standard deviation is given by :-

\sqrt{\dfrac{(n-1)s^2}{\chi_{\alpha/2}}}

Given : Sample size = n=24

Significance level : \alpha:1-0.99=0.01

Using the chi-square distribution table , the critical values would be :-

\chi_{n-1,\alpha/2}=\chi_{23, 0.005}=44.18127525

\chi_{n-1,1-\alpha/2}=\chi_{23, 0.995}=9.26042478

Then , a 99% confidence interval for the population standard deviation will  be :-

\sqrt{\dfrac{(23)(50)^2}{44.18127525}}

8 0
3 years ago
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