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galben [10]
3 years ago
12

Help! I’ll give brainliest if I can!

Mathematics
1 answer:
hoa [83]3 years ago
5 0

Answer:

1) I can use the hours and number of packages to help solve the problem

2) I go to the number 3 and go up from there (answer 45)

3) the packages a driver can deliver in a 7 hour day is 105

4)divided 15 from 120

Step-by-step explanation:

1) question 4) you find out how much packages he deilivers in an hour

2) question 4) its 15

3) question 4) divided 10 from 120 :)

You might be interested in
Jay needs 19 quarts more for outside of barn uses 107 quarts in all how many gal will be used on inside
Jet001 [13]

Answer:

This equation belongs to One variable linear equation  because there is one variable = x and the exponent number is one

solving equations :

x= 44 quarts

3 0
3 years ago
At Otto’s egg farm, Otto has found that when he charges $0.05 per egg, he sell so many eggs that he cannot keep up with the dema
PilotLPTM [1.2K]

Answer:

a) P(c) = xc² + yc + z, and P(.15) = $124, P(.05) = 0, P(.17) = 0. Thus:

(#1) .0225x + .15y + z = 124

(#2) .0025x + .05y + z = 0

(#3) .0289x + .17y + z = 0

Subtracting #2 from #3: (#4) .0264x + .12y = 0

Subtracting #2 from #3: (#5) .02x + .1y = 124

Subtracting 1.2×#5 from #4: .0024x = -148.8 → x= -62000

Using this value of x in #5: -1240 + .1y = 124 → y = 13640

Using x and y in #1: -1395 + 2046 + z = 124 → z = -527

P(c) = -62000c² + 13640c - 527

b) To find the maximum of P(c), find a such that P'(a) = 0

-124000c + 13640 = 0

c = .11

At this price, his profit would be $223.20

3 0
3 years ago
One of the smallest pools on the ship has about 45,000 gallons of water in it.
gtnhenbr [62]

Amount of water in the pool at the end of the day is 5457798.7 gallons

<u>Explanation:</u>

Given:

Initial amount of water in the pool = 45,000 gallons

Increase in amount = 0.75 in per minute

Time, t = 1 day

t = 24 X 60 min

t = 1440 min

So,

Increase in amount of water in 1 day = 0.75 in X 1440

                                                             = 1080 in

Volume of 1080 in of water = (1080 in)³

Volume from cubic inch to gallon = 5453298.7 gallon

Amount of water in the pool at the end of the day = 45000 + 5453298.7 gallon

                                                                                   = 5457798.7 gallon                                          

5 0
3 years ago
A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?​
Nataliya [291]

9514 1404 393

Answer:

  3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

  A = LW = 12a^2

  P = 2(L+W) = 14a

Using the second equation, we can find L:

  L +W = 7a . . . . . divide by 2

  L = 7a -W

Substituting into the area formula gives the quadratic ...

  (7a -W)(W) = 12a^2

  W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

  (W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

  W = 3a, L = 4a

  W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

5 0
3 years ago
The vertices of ΔGHI are G (2, 4), H (4, 8), and I (8, 4). The vertices of ΔJKL are J (1, 1), K (2, 3), and L (4, 1). Which conc
Klio2033 [76]

Answer:

They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

The first step is finding the sides of each triangle.

In triangle GHI, we have that:

GH = sqrt((4-2)^2 + (8-4)^2) = 4.4721

HI = sqrt((8-4)^2 + (4-8)^2) = 5.6569

IG = sqrt((2-8)^2 + (4-4)^2) = 6

Now, for the triangle JKL, we have:

JK = sqrt((2-1)^2 + (3-1)^2) = 2.2361

KL = sqrt((4-2)^2 + (1-3)^2) = 2.8284

LJ = sqrt((1-4)^2 + (1-1)^2) = 3

The triangles are not congruent, because the sides are different

They are similar, because their sides have a proportion (sides of GHI are 2 times the sides of JKL). If they are similar, they have the same angles.

The ratio of their corresponding sides is 1:2, not 1:3

The ratio of their corresponding angles is 1:1, not 1:3

3 0
3 years ago
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