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3 years ago

Determine whether the relation is a function. {(-4, 1), (0, 0), (4, 0), (0, 4)}

Mathematics

2 answers:

mash [69]3 years ago

8 0

It isn’t because the x’s is matching

olga nikolaevna [1]3 years ago

6 0

Answer:

It isn't

Step-by-step explanation:

An x can't have to y's

way to remember: x=exes y=wives

you can have multiple exes (x's) but only one wife (y's)

0 has two y's

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Use the formula, I = PRT, to find the time if | = $387.50, P = $1,550, and R = 12.5%

stiks02 [169]

Answer:

T = 2

Step-by-step explanation:

Take the given formulaer

I = PRT

And plug in the variables you know (I, P, R)

387.50 = 1,550(.125)T

(12.5% becomes .125 after you divide it by 100, because precents are really just fractions out of 100)

387.50 = 193.75T

T = 2

8 0

2 years ago

In ΔPQR, find the measure of ∡P.

Artyom0805 [142]

Answer:

30.4°

Step-by-step explanation:

< P = arc tan QR/PQ

= arc tan 33.8/57.6

= arc tan 0.5868

= 30.4°

8 0

3 years ago

Find parametric equations for the line. (Use the parameter t.) The line through the origin and the point (2, 6, −1) (x(t), y(t),

dimaraw [331]

Answer:

Step-by-step explanation:

i think its 2 with the remainder of 8

5 0

3 years ago

Rewrite the expression as an equivalent ratio of logs using the indicated base.log17(52.875) to base 10.

s2008m [1.1K]

Answer:

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Step-by-step explanation:

Given

$log_{17}(52.875)$

Required

Convert to base 10

To do this, we make use of the following logarithm laws;

$log_ba = \frac{log_{10}a}{log_{10}b}$

In the given parameters;

$a = 52.875$

$b = 17$

Substitute these values in $log_ba = \frac{log_{10}a}{log_{10}b}$

$log_{17}52.875 = \frac{log_{10}52.875}{log_{10}17}$

Represent as a ratio

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Hence;

$log_{17}(52.875)$ is represented as $log_{17}52.875 = log_{10}52.875 : log_{10}17}$

7 0

3 years ago

Where is Point A located on the coordinate grid?

Leya [2.2K]

Answer:

The answer is Quadrant I.

Step-by-step explanation:

Start from the upper left square to the right and go to the bottom left square after you move from there.

Quadrant I is like Quadrant 1. Quadrant II is like Quadrant 2 and so forth. So if each Quadrant is the square with the lines dividing it, your answer is Quadrant I.

7 0

3 years ago

Read 2 more answers