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Ugo [173]
2 years ago
8

4+5

rac{x}{y} 3x^{2} - 3x^{2}" alt="4+5\frac{x}{y} 3x^{2} - 3x^{2}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Ronch [10]2 years ago
5 0

Answer:

58 +  \frac{ {15x}^{3} }{y}  -  {3x}^{2}

Step-by-step explanation:

1) Use this rule: a/b × c/d = ac/bd.

4 + 54 +  \frac{5x \times  {3x}^{2} }{y}  -  {3x}^{2}

2) Take out the constants.

4+54 +  \frac{(5 \times 3) {xx}^{2} }{y}  -  {3x}^{2}

3) Simplify 5 × 3 to 15.

4 + 54 +  \frac{ {15xx}^{2} }{y}  -  {3x}^{2}

4) Use the product rule: x^a x^b = x^a + b.

4 + 54 +  \frac{15xx^{2} }{y}  - 3x^{2}

5) Simplify 1 + 2 to 3.

4 + 54 +  \frac{15 {x}^{3} }{y}  -  {3x}^{2}

6) Collect like terms.

(4 + 54) +  \frac{15 {x}^{3} }{y}  -  {3x}^{2}

7) Simplify.

58 + \frac{ {15x}^{3} }{y}  -  {3x}^{2}

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>58</u><u> </u><u>+</u><u> </u><u>15x</u><u>³</u><u> </u><u>/</u><u> </u><u>y</u><u> </u><u>-</u><u> </u><u>3x</u><u>²</u>.

evablogger [386]2 years ago
3 0
DONT TRUST LINKS ! They not even helping you
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Answer:

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3 years ago
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D3<br> Find two numbers between 100 and<br> 150 that have a HCF of 22.
vesna_86 [32]

The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

<h3>Highest common factors</h3>

The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

According to the question, we are to find two numbers between 100 and

150 that have a HCF of 22.

In order to do that we will<u> multiply 22 by the values 5 and 6</u>

First number = 22 * 5 = 10

Second number = 22 * 6 = 132

Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

Learn more on HCF here; brainly.com/question/21504246

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4 0
1 year ago
Please help with this. I only need help with the first question I have the second one figured out,
lutik1710 [3]

Answer:

m∠WZX = 41°

Step-by-step explanation:

diagonals bisect angles and opposite angles are congruent

therefore, ∠WXY ≅ ∠WZY

∠WZY must equal [360 - 2(68)] ÷ 2 which equals 112°

If ∠WXZ = 71° then so does ∠XZY

Which means that ∠WZX must equal 112-71 which is 41°

6 0
3 years ago
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An empty bucket is placed under a faucet dripping at a constant rate of 4 milliliters per minute. With the given information, wh
GarryVolchara [31]

the answer is true i think

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Tickets to a football final are selling well. On Thursday, 47 of the tickets are sold. On Friday, 14 of the tickets are sold. Wh
lbvjy [14]

The question seems incomplete ; as the total number of tickets to be sold isn't given.

Answer:

61 / X

Step-by-step explanation:

Let's take the total Number of tickets to be sold as : X

Number of tickets sold on Thursday = 47

Number sold on Friday = 14

Fraction of tickets available for sale on Saturday :

(Total number of tickets already sold) / Total number of tickets to be sold

(Thursday + Friday sales) / total number of tickets to be sold

Fraction available for sale on Saturday = (47+14) / X

Fraction available for sale on Saturday = 61 / X

Kindly put value of x = total number of tickets available for sale to get the exact fraction.

6 0
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