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Rudik [331]
3 years ago
12

Which situations can be simulated using this spinner? Select three options.

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0
Choosing a color, number, or restaurant
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What is the value of x<br>1. 124<br>2. 62<br>3. 112<br>4. 68<br>explain why the answer is correct ​
Fynjy0 [20]

Answer:

<h2>3.112<em> </em><em>because</em><em> </em><em>5</em><em>6</em><em>+</em><em>5</em><em>6</em><em>=</em><em>1</em><em>1</em><em>2</em></h2>
3 0
3 years ago
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If g(x)=f(x+1), then g(x) translates the function f(x) 1 unit _[blank]_.
galina1969 [7]

answer: right

reason: because you are talking about the x axis so if you go left that would be a negative and you cant go up and down bc that's the y axis so the only way to go is right

hope this helped

4 0
3 years ago
Please help me ASAP easy problem giving brainlist!!
never [62]

Answer:

x ≥ 1

Step-by-step explanation:

Since it's a closed circle x could also be equal to 1. Also, since the arrow is pointing away from 1 the answer of x is greater than 1, therefore the answer is x ≥ 1.

8 0
3 years ago
PLEASE HELP ITS DUE IN 5 MINS WILL MARK THE BRAINLEST PLEASE HURRY ITS DUE
Sidana [21]

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3 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 &lt; 0&lt; 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
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