Answer:
<em>See Reasoning Below</em>
Step-by-step explanation:
To prove that AB = BL, or in other words AB ≅ BL, let us consider the triangles CED and BEL. If we were to prove they were congruent, then by CPCTC ( corresponding parts of congruent triangle are congruent ) DC ≅ BL. As AB ≅ DC by " Properties of Parallelogram " it would be that through transitivity, AB ≅ BL / AB = BL;
Now for " part 2 " we can consider that AB = DC, from part 1. If AB = BL, then AL = 2 ( AB ) by the Partition Postulate. AB = DC, so we can also say that AL = 2 ( DC ) - Proved
See attachment in statement reasoning form for part 1;
Use the sin(a - b) formula.
<span>sin(90 - x) = </span>
<span>sin90 cosx - cos90 sinx = </span>
<span>1 cosx - 0 sinx = </span>
cosx
Answer:
brainly gandhiji went to dandi march
Step-by-step explanation:
Mark brainliest
<span>An obtuse triangle will have one and only one obtuse angle. </span>
<span>The other two angles are acute angles.</span>
<span>The sum of the two angles other than the obtuse angle is less than 90º.<span /></span>
<span><span>The side opposite to the obtuse angle is the longest side of the triangle.</span></span>
<span><span>
</span><span>The points of concurrency, the Circumcenter and the Orthocenter lie outside of an obtuse triangle, while Centroid and Incenter lie inside the triangle.
</span></span>
I assume we are solving for x see attachment.
