What we have to do is to find the largest common divisor of the two numbers: 12 and 30. It must be at least 2, since they're both even, and at least 3 since both are divisible by 3, so that means that it it also must be at least 6 (2*3=6; if they're divisible by 2 and 3, they must be both divisible by 6).
But they have no bigger divisor than this.
So that means that the number of groups will be 6 (both groups can be divided into 6). It will have 2 (12/6=2) newcomers and 5 (30/6=5) advanced swimmers.
Answer:
45 sweets.
Step-by-step explanation:
6:2:1
To solve how many Jim and Dan has I did 6 x n and 1 x n until the difference of the two numbers equaled 25.
6 x 5 = 30
1 x 5 = 5
30 - 5 = 25.
So, Jim as 30 candy and Dan has 1. How much does David have?
Just do the same thing but with 2 x n:
2 x 5 = 10.
Now add them together:
30 + 10 + 5 = 45.
Therefore, 45 sweets!
Answer:
a.
Step-by-step explanation:
Probability that is a AB type blood given is a Male
P(AB/M) = 42/500 = 21/250
Probability that they are Male with an AB type blood out of all AB type blood people = Probability that is a Male out of all students
P(M∩AB) = P(M)
(42/105) = (500/1,250)
.4 = .4 ✅
The events "the student is male" and "the student has blood type AB" are independent events.
70 percent is a c hope that helped
Step-by-step explanation:
5+7=12 books all together