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2 years ago

What’s the answer to this math question?

Mathematics

1 answer:

Doss [256]2 years ago

3 0

Answer:

Step-by-step explanation:

(0, 3) (4, 2)

x2.y2. x1 y1

$m = \frac{y2}{x2}-\frac{y1}{x1}$

$m=\frac{3}{0}- \frac{2}{4}$

= 1/-4

slope = 1/-4

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Dominik [7]

Answer:

y = x + 3y = x - 1

Step-by-step explanation:

Just graph them!

Hope I could help.

5 0

3 years ago

3/4 - 2/7 = ? pls help me because I can get grounded

Leona [35]

Answer:

1/7

Step-by-step explanation:

&&5_4_&&&&&&&&&&&&&---

7 0

3 years ago

If the boy is 5’6 tall and his shadow is 4 ft and the shadow of the pole 18 ft determine the height of the pole to the nearest 1

Dominik [7]

The answer is 24.7ft

7 0

3 years ago

What is the sum 13,094 259,728?

fgiga [73]

Thank you for posting your question here at brainly. I will assume that the equation is that 13,094 + 259,728. Below is the solution:

13,094 + 259,728 = 272,822

Sum is the total amount resulting from the addition of two or more numbers, amounts, or items.

6 0

3 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

Answer:

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

Solution:

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

3 years ago