It can be used to hold a prisoner for the police
Answer:
15/56
Step-by-step explanation:
5 people have a license
3 people don't
? = Probability that first person has a license and second does not
We can divide the problem into two sections, the first being the probability of the first person having a license, and the second section is the probability that the second person doesn't have a license.
P1 = Probability of the first person having a license, there are 5 out of 8 person having a license, thus P1 = 5/8.
P2 = Probability of the second person having a license. There are 3 people not having a license, out of 8-1 = 7 persons available, since one is taken already from the first choice, therefore P2 = 3/7.
P1 and P2 are dependent events, thus P(1,2) = P1 * P2.
P(1,2) = P1 * P1 = 5/8 * 3/7 = 15/56
