Question

20 points need this fast pls

Answer 1

Answer:

$m\angle AED=90\degree$

$m\angle DAE=53\degree$

$m\angle BCE= 53\degree$

Step-by-step explanation:

ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.

Diagonals of a rhombus bisects at right angles.

$\therefore m\angle AED=90\degree$

$In\: \triangle AED$

$m\angle DAE=90\degree-m\angle EDA$

$m\angle DAE=90\degree-37\degree$

$m\angle DAE=53\degree$

$\because m\angle BCE= m\angle DAE$

(Alternate angles)

$\therefore m\angle BCE= 53\degree$