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sammy [17]
3 years ago
15

20 points need this fast pls

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

m\angle AED=90\degree

m\angle DAE=53\degree

m\angle BCE= 53\degree

Step-by-step explanation:

ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.

Diagonals of a rhombus bisects at right angles.

\therefore m\angle AED=90\degree

In\: \triangle AED

m\angle DAE=90\degree-m\angle EDA

m\angle DAE=90\degree-37\degree

m\angle DAE=53\degree

\because m\angle BCE= m\angle DAE

(Alternate angles)

\therefore m\angle BCE= 53\degree

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