All categories

3 years ago

7 is 5% of what number

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

8 0

Answer:

the answer is 140 , please let me know if I am wrong.

kipiarov [429]3 years ago

3 0

let a number be x

x of 5%=7

x×5÷100=7

x=7×100÷5

x=140

You might be interested in

103,727,495 in a word form

3241004551 [841]

103,727,495 in word form is: one hundred three million, seven hundred twenty-seven thousand, four hundred ninety-five.

3 0

4 years ago

What is the second step in costructing congruent angles?

sattari [20]

Answer:

Given an angle formed by two lines with a common vertex, this page shows how to ... The above animation is available as a printable step-by-step instruction sheet, which can be ... This construction works by creating two congruent triangles

Step-by-step explanation:

3 0

3 years ago

What is the answer to this please help!

Butoxors [25]

$z+(-0.72)=-2.5\\\\\text{Step 1}:\ x+(-0.72)+(-0.72)=-2.5+(-0.72)\qquad\text{ERROR}\\\\CORRECT\ IS:\ x+(-0.72)-(-0.72)=-2.5-(-0.72)\\\\\text{Step 2}:\ x=-2.5+0.72\\\\\text{Step 3}:\ x=-1.78$

Subtract, not add, -0.72 from both sides.

6 0

3 years ago

If my assignment is worth 14% of my quiz weight which is 27% of my total weight what is the weight of that assignment

Nimfa-mama [501]

Answer:

3.785%

Step-by-step explanation:

Assignment is 14% of the quiz

=> Assignment = 14% of the quiz

Quiz is 27% of the total weightage

=> 14% of 27%

14% of 27%

= 0.14 x 27 = 3.785%

The assignment is 3.785% of the total weightage.

6 0

3 years ago

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$

$\boxed{ \frak \red{brainlysamurai}}$

6 0

2 years ago