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Ymorist [56]
3 years ago
7

Jane has several legal documents to type. Jane completes an average of 7 documents per 15 minutes. Her completion of one documen

t is independent of any other one.
a) Let N be the number of documents Jane completes between 9:00am and 10:00am. What are the distribution, parameter(s), and support of N?
b) Determine the probability that Jane completes 30 documents between 9:00am and 10:00am.
c) What is the probability that Jane completes 58 documents between 2:00pm and 4:00pm.
d) Determine the probability that Jane completes 30 documents between 9:00am and 10:00am and 40 documents between 1:00pm and 2:30pm.
e) What is the standard deviation for the number of documents Jane will complete between 3:00pm and 5:45pm?
f) If Jane is paid at a rate of 1 dollar and 25 cents per document how much can she expect to make for a day in which she has 6 and a half hours of straight typing?

Mathematics
1 answer:
liq [111]3 years ago
8 0

Answer:

Step-by-step explanation:

check the attachments below for step by step solution

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Sarah bought 18 boxes of 65 pens at $12 a box. She sold 378 of them at 3 for $1.00 and the rest at 4 for $1.00. Find her total p
KonstantinChe [14]

Answer:

$108

Step-by-step explanation:

1 box = $12

18 boxes = 12×18 = $216

Total = 18×65 = 1170 pens

Cost price, Cp = $216

3 = $1

378 = 378/3 = $126

1170-378= 792 pens remaining

4 = $1

792 = 792/4 = $198

Total selling price, sp = 126+198 = $324

Profit = Sp - Cp = 324 - 216 = $108

8 0
3 years ago
Given the diagram below find x, and the measure of
Sophie [7]

Answer:

8, 40 , 50

Step-by-step explanation:

the measure of A is 90°

so 5x + 7x - 6 = 90

now.. to find the x

5x + 7x - 6 = 90

5x + 7x = 90 + 6

12x = 96

x = 96/12

x = 8

so the measure of angle A1 is (5*8) = 40

the measure of angle A2 is (7*8-6) = 50

finaly the angle A is (50+40) = 90

8 0
3 years ago
Each of the four sets a1, a2, a3, and a4 contains four elements. the intersection of every i of these four sets (2 < i < 4
hammer [34]

Answer:

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Step-by-step explanation:

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Answer:

its 45 degrees celcius

Step-by-step explanation:

7 0
3 years ago
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The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
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