Question

Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.

Answer 1

Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.
ƒ(x) = –5x2 + 2x –1
First, Substitute x by -3 in the formula of the function and calculate as follows.
ƒ(-3) = –5x2 + 2x –1
Apply the Order of Operations.
ƒ(-3) = –5(-3)^2 + 2(-3) –1
Simplify
ƒ(-3) = –5(9) + 2(-3) –1
ƒ(-3) = –45 -6 –1
ƒ(-3) = -52

Therefore, The function of ƒ(–3) for ƒ(x) = –5x2 + 2x –1 is -52