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sukhopar [10]
3 years ago
6

Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0
<span>Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.
</span>ƒ(x) = –5x2 + 2x –1
First, Substitute x by -3 in the formula of the function and calculate as follows.
ƒ(-3) = –5x2 + 2x –1
Apply the Order of Operations.
ƒ(-3) = –5(-3)^2 + 2(-3) –1
Simplify
ƒ(-3) = –5(9) + 2(-3) –1
ƒ(-3) = –45 -6 –1
ƒ(-3) = -52

Therefore, The function of ƒ(–3) for ƒ(x) = –5x2 + 2x –1 is -52

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Answer:

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Answer:

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amm1812

Answer:

a)   x₁ = 14

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b) x = 4

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Step-by-step explanation:

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x₁,₂ = [ -b ± √b² -4ac ]/2a

x₁,₂ = [ 8  ±√(64) + 336 ]/2

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Taking derivatives on both sides of the equation we get

P´(x) = - 8x + 32  ⇒  P´(x) = 0     - 8x + 32

x = 32/8

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to get  a profit :

P = - 4*(4)² + 32*(4) + 336

P(max) = -64  + 128 + 336

P(max) = 400           or  400* 10000 =  4000000

     

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Answer:

Step-by-step explanation:

The interest after 8 years is $240

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Hope this helps!

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