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3 years ago

Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.

1 answer:

6 0

Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.
ƒ(x) = –5x2 + 2x –1
First, Substitute x by -3 in the formula of the function and calculate as follows.
ƒ(-3) = –5x2 + 2x –1
Apply the Order of Operations.
ƒ(-3) = –5(-3)^2 + 2(-3) –1
Simplify
ƒ(-3) = –5(9) + 2(-3) –1
ƒ(-3) = –45 -6 –1
ƒ(-3) = -52

Therefore, The function of ƒ(–3) for ƒ(x) = –5x2 + 2x –1 is -52

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Step-by-step explanation:

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h) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$

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