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3 years ago

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Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.

1 answer:

Kisachek [45]3 years ago

6 0

<span>Evaluate ƒ(–3) for ƒ(x) = –5x2 + 2x –1.
</span>ƒ(x) = –5x2 + 2x –1
First, Substitute x by -3 in the formula of the function and calculate as follows.
ƒ(-3) = –5x2 + 2x –1
Apply the Order of Operations.
ƒ(-3) = –5(-3)^2 + 2(-3) –1
Simplify
ƒ(-3) = –5(9) + 2(-3) –1
ƒ(-3) = –45 -6 –1
ƒ(-3) = -52

Therefore, The function of ƒ(–3) for ƒ(x) = –5x2 + 2x –1 is -52

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