3 years ago

Given the formula solve for x. y - y1 = m(x-x1)

1 answer:

5 0

Answer:

$y - y' = m(x - x') \\ (x - x') = \frac{(y - y')}{m} \\ x = \frac{(y - y')}{m} + x'$

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$\text{The equivalent expression of } (x^3)(x^{-2}) \text{ is } x$

Solution:

Given that,

Given expression is:

$(x^3)(x^{-2})$

We have to write the equivalent expression

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$(x^3)(x^{-2})$

Here the base is same and exponents are 3 and -2

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Thus the equivalent expression is x

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