2 years ago

Iff(x)=3x+1 and f^-1= x-1/3,then f(2)=

Mathematics

1 answer:

maks197457 [2]2 years ago

3 0

Answer:

Step-by-step explanation:

f(x) = 3x + 1 ⇒ f(2) = 3×2 + 1 = 6 + 1 = 7

You might be interested in

In na hour , a jogger burns about 4 calories pero pound of body weight. How Manu calories will a jogger who weighs 151 pounds in

Alex777 [14]

This is a rate*unit problem.

So, 4 calories per pound x 151 pounds

$4\times151=604$

He will burn 604 calories in one hour

6 0

2 years ago

Please help it’s very cunning

gregori [183]

The answer to you question is B

7 0

2 years ago

Find the difference: (6y3 + 17y − 3) − (4y3 − 11y + 9)

earnstyle [38]

<span>(6y3 + 17y − 3) − (4y3 − 11y + 9)
</span>= 6y3 + 17y − 3 − 4y3 + 11y - 9
= 2y3 + 28y - 12

3 0

2 years ago

Your bedroom ceiling if 10 feet high and is two-thirds as high as the living room ceiling. Write and solve an equation to find t

timurjin [86]

Ht of ceiling = 10 ft which is two-thirds of living rm ceiling
Ht of living rm ceiling = 2/3x = 10 ft
2/3h = 10 ft
2/3h times 3/2 to solve for h = 10 times 3/2
h = 30/2
h = 15 ft

5 0

2 years ago

Please help!!! 30 minutes left

NeX [460]

Answer:

Option "D" is correct.

Step-by-step explanation:

$\frac{a^{3}b^{-2} }{ab^{-4} }$

To eliminate negatives

They are interchanged thus it gives us option D.

7 0

2 years ago

Iff(x)=3x+1 and f^-1= x-1/3,then f(2)=​

Iff(x)=3x+1 and f^-1= x-1/3,then f(2)=