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Kisachek [45]
2 years ago
6

Write an equation in slope intercept form for the line passing through (2, 6) with a slope of -3

Mathematics
1 answer:
mixer [17]2 years ago
4 0

Answer:

y=-3x+12

Step-by-step explanation:

y-y1=m(x-x1)

y-6=-3(x-2)

y-6=-3x+6

y=-3x+6+6

y=-3x+12

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B, there are two sections that say 1, and there are less sections then the other one with two ones
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2 years ago
The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

  • Revenue is <u>Q₂ < $7,500 < Q₃</u>
  • The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

  • Revenue; <u>Q₂ < $7,100 < Q₃</u>
  • The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

  • Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193

From the Z-Table, we have;

The percentile= 0.7291

  • Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

  • Z = \dfrac{7500 - 6611}{3580} \approx 0.25

From the Z-Table, we have;

The percentile = <u>0.5987</u>

  • Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

  • The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

  • The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

  • The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

  • The interquartile range = <u>6075</u>

Learn more here:

brainly.com/question/21133077

brainly.com/question/23305909

5 0
1 year ago
A grocery store purchases bags of chips for $2 and marks up the price by 162%. The store is having a sale where everything is on
drek231 [11]

Answer:

4.62

Step-by-step explanation:

2 * 1.62= 3.24

new cost is $3.24 + 2 = 5.24

5.24 * .12 = .62 discount

5.24 - .62

4.62

7 0
2 years ago
Read 2 more answers
This is Core Focus: Working With Scientific Notation
asambeis [7]
A. 3272.4
b.349.92
c. 198.432
d. 194.688
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2 years ago
There were 324 adults surveyed. Among the participants, the mean number of hours of sleep each night was 7. 5 and the standard d
NeTakaya

The margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

<h3>What is the margin of error?</h3>

The margin of error can be defined as the amount of random sampling error in the results of a survey. It is given by the formula,

\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\frac{\sigma^{2}}{n}}

\text{MOE} = margin of error

\gamma = confidence level

z_{\gamma} = quantile

σ = standard deviation

n = sample size

As it is given that the sample size of the survey is 324, while the standard deviation of the survey is 1.6.

We know that the value of the z for 95% confidence interval is 1.96. Therefore, using the formula of the standard of error we can write it as,

\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\dfrac{\sigma^{2}}{n}}\\\\\text{MOE}_{\gamma}=1.96 \times \sqrt{\dfrac{1.6^{2}}{324}}\\\\\text{MOE}_{\gamma}=0.1742

Hence, the margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

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5 0
2 years ago
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