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3 years ago

Help plz 5 or 3 pts or 10 isk :)

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

The solution is X=10.

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Solve for 2x^2-4x+5=6

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in your values
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3 years ago

Write as a decimal number. 9-10

Ad libitum [116K]

Answer:

Step-by-step explanation:

9 divided by 10

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2 years ago

Five packets of almonds cost 2m dollars. Mandy buys 3 packets of almonds. How much change does she receive if she paid with a $1

Vitek1552 [10]

Answer:

Step-by-step explanation:

if its $2 per packet and he is buying 3 do 2x3 which is 6 then 10-6 which is $4

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2 years ago

What is the slope?

Pavlova-9 [17]

Answer:5/3

Step-by-step explanation:

choose two coordinates (40,0) and (70,50) then use y2-y1/x2-x1. when you plug the numbers in 50-0/70-40, subtract 50/30, and simplify, you get 5/3

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2 years ago

Use the Fundamental Theorem of Line Integrals to calculate ∫c F⃗ ⋅dr⃗ exactly, if F⃗ =3x2/3i⃗ +ey/5j⃗ , and C is the quarter of

nignag [31]

It looks like the vector field is

F(x, y) = 3x ^(2/3) i + e ^(y/5) j

Find a scalar function f such that grad f = F :

∂f/∂x = 3x ^(2/3) => f(x, y) = 9/5 x ^(5/3) + g(y)

=> ∂f/∂y = e ^(y/5) = dg/dy => g(y) = 5e ^(y/5) + K

=> f(x, y) = 9/5 x ^(5/3) + 5e ^(y/5) + K

(where K is an arbitrary constant)

By the fundamental theorem, the integral of F over the given path is

∫c F • dr = f (0, 1) - f (1, 0) = 5e ^(1/5) - 34/5

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3 years ago