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3 years ago

6

Determination of the energy imparted to matter by radiation is the subject of ______. A. photometry B. magnification C. dosimetr

y D. optometry

1 answer:

givi [52]3 years ago

7 0

Answer:

dosimetry

Explanation:

dosimetry is the determination of energy imparted to matter by radiation

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A force of 200 N is applied at piston A, which has a surface area of 4

stira [4]

Answer:

60 cm²

Explanation:

Pressure = Force / Surface area

This is a 2 stage problem which requires working out pressure of piston A and then using that pressure from piston A to calculate the surface area of piston B

Firstly work out pressure of Piston A:

Pressure = 200 / 4

Pressure = 50 N/cm²

Then work out the Surface area of piston B :

Since the pressure is transferred the pressure stays the same so :

Surface area = Force / Pressure

Surface area = 3000 / 50

Surface area = 60 cm²

7 0

4 years ago

A piece of rope is pulled by two people in a tug-of-war. each exerts a 400-n force. what is the tension in the rope?

Leokris [45]

Newtons 3.law: Action = Reaction

If a body exerts a force on a rope of 400 N the rope exerts a force on the body of 400N also. So the tension in the rope is 400N. See pictures below.

3 0

4 years ago

Read 2 more answers

Pls help I will give brainlist and don’t give me a link I can’t open them

dezoksy [38]

Answer:

200

Explain:

I have a big brain

5 0

3 years ago

What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms

Alexus [3.1K]

Answer:

1.5F

Explanation:

Using

E= F/q

Where F= force

E= electric field

q=charge

F= Eq

So if qis tripled and E is halved we have

F= (E/2)3q

F= 1.5Eq=>> 1.5F

4 0

3 years ago

With what tension must a rope with length 2.90 m and mass 0.125 kg be stretched for transverse waves of frequency 42.0 Hz to hav

Vesnalui [34]

Answer:

41.64 N

Explanation:

Applying,

v = √(T/m')................ Equation 1

Where v = velocity of the wave, T = Tension of the rope, m' = mass per unit length of the rope.

make T the subject of the equation,

T = v²m'................. Equation 2

But,

v = λf............... Equation 3

Where λ = wavelength, f = frequency

And

m' = m/L........... Equation 4

Where m = mass of the rope, L = length of the rope

Substitute equation 3 and equation 4 into equation 2

T = (λf)²(m/L).............. Equation 5

From the question,

Given: λ = 0.740 m, f = 42 Hz, m = 0.125 kg, L = 2.9 m

Substitute these values into equation 5

T = (42×0.74)²(0.125/2.9)

T = 41.64 N

6 0

3 years ago