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3 years ago

Are these questions correct ?

Mathematics

1 answer:

balandron [24]3 years ago

7 0

Answer:

not all of em

Step-by-step explanation:

some are

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Answer it like this

Vaselesa [24]

1. Radius is 7
2. Radius is 22 sorry don’t know the diameter

5 0

3 years ago

Read 2 more answers

a forest ranger correctly rounded the number of visitors to a park to be 120,000 write a number that could be the actual number

Andre45 [30]

Answer: this isnt of my own, autor of the answer was brainly.com/app/profile/14278780/answers

124,000 can be the actual number

Step-by-step explanation:

* Lets explain how to solve the number

- The number of visitors to the park is 120,000 visitors rounded

to the nearest ten thousands

- The round to nearest digit means look to the digit before this

digit if < 5 we put all the digits before the rounded digit zero and

keep it as it, if the number before the rounded digit is ≥ 5 we put

all the digits before the rounded digit zero and add the rounded

digit by 1

- Ex:

# To round 12,345 to the nearest thousand look to the hundred

digit (3), 3 < 5 , then the rounded number is 12,000

# To round 12,745 to the nearest thousand look to the hundred

digit (7), 7 > 5 , then the rounded number is 13,000

- To find the actual number lets do these steps

1. Divide the ten thousands by 2

∵ 10,000 ÷ 2 = 5,000

2. Add the result and subtract the result from the rounded number

∵ 120,000 - 5000 = 115,000

∵ 120,000 + 5000 = 125,500

3. The actual number is between these two numbers

∴ 115,000 ≤ actual number < 125,000

- Remember: we can not take the number 125,000 as the actual

number because when we round it to the nearest ten thousand

the answer will be 130,000

∴ You can chose any numbers belongs to this range

* I will chose 124,000 can be the actual number

8 0

3 years ago

For each rational expression, identify the greatest common factor, write the expression in factored form, and simplify.

podryga [215]

Answer:

1) $9a,\frac{3^{3n}}{5^{n^{5}}},\frac{x+x^{3}}{x^{3}},\frac{a}{a^{5}-1},\frac{3b+1}{5b^{3}}, \frac{3y}{y^{2}-2},\frac{2x^{2}+4x-1}{3}, \frac{(p^{4}-5q^{2})}{(2p^{2}q^{3}+6p^{4}q^{2})}$ 2) $\frac{xy^{4}+7x^{5}y^{2}+49}{2x^{5}y^{2}}$

Prime factorize the parameters 7,49,28,343 pick its GCF=7. As for the variables choose the ones raised to the least exponent and divide each term by this.

Then, after that part. All that's left is a simplification dividing the members by the common monomial.

Step-by-step explanation:

1) Let's proceed this way. For the numbers, to find the GCF is simply to Prime factor the numbers and pick greatest common factor. When it comes to variables the point is to choose the variable with the least exponent.

$\frac{27a^{4}}{3a^{3}}\: GCF=3a^{3}\Rightarrow \frac{27a^{4}:3a^3}{3a^{3}:3a^{3}}=9a\\\\\frac{15m^{5n}}{25m^{2n^{6}}}\:GCF=5 \Rightarrow \frac{15m^{5n}:5m^{2n}}{25m^{2n^{6}}:5m^{2n}}=\frac{3^{3n}}{5^{n^{5}}}\\\\\frac{x^{4}+x^{6}}{x^{3}}\:GCF=x^3\Rightarrow \frac{x^{4}:x^{3}+x^{6}:x^{3}}{x^{3}:x^{3}}\Rightarrow \frac{x+x^{3}}{x^{3}}$

$\frac{a^{5}}{a^{9}-a^{4}}\:GCF:a^{4}\Rightarrow \frac{a^{5}:a^{4}}{a^{9}:a^{4}-a^{4}:a^{4}}\Rightarrow \frac{a}{a^{5}-1}\:or\:\frac{a^{4}(a)}{a^{4}(a^{5}-1)}=\frac{a}{a^{5}-1}\\\frac{3b^{2}+b}{5b^{4}}\:GCF=b\Rightarrow \frac{b(3b+1)}{b(5b^{3})}=\frac{3b+1}{5b^{3}}\\\frac{21y^{3}}{7y^4-14y^2}\:GCF=7y^{2}\Rightarrow \frac{7y^{2}(3y)}{7y^{2}(y^{2}-2)}\Rightarrow \frac{3y}{y^{2}-2}$

$\frac{6x^{4}+12x^{3}-3x^{2}}{9x^{2}}\:GCF=3x^{2}\Rightarrow \frac{3x^{2}(2x^{2}+4x-1)}{3x^{2}(3)}\Rightarrow \frac{2x^{2}+4x-1}{3}$

$\frac{2p^{5}q-10pq^{3}}{4p^{3}q^{4}+12p^{5}q^{3}}\:GCF=2pq \Rightarrow \frac{2pq(p^{4}-5q^{2})}{2pq(2p^{2}q^{3}+6p^{4}q^{2})}=\frac{(p^{4}-5q^{2})}{(2p^{2}q^{3}+6p^{4}q^{2})}$

2,3) <em>Write your own example of a rational expression and demonstrate how to simplify the expression using GCF (greatest common factor).</em>

Write a rational expression with a gfc that has both a numeric part and a variable part.

Identify gfc and show how to simplify using gfc.

Well, similarly, to the previous ones. Prime factorize the parameters 7,49,28,343 pick its GCF=7. As for the variables choose the ones raised to the least exponent and divide each term by this.

Then, after that part. All that's left is a simplification dividing the members by the common term as it follows:

$\frac{7x^{2}y^{6}+49x^{6}y^{4}+343xy^{2}}{28x^{6}y^{4}}\Rightarrow GCF=7xy^{2}\Rightarrow \frac{7xy^{2}(xy^{4}+7x^{5}y^{2}+49)}{7xy^{2}(2x^{5}y^{2})}\Rightarrow \frac{xy^{4}+7x^{5}y^{2}+49}{2x^{5}y^{2}}$

3 0

3 years ago

42−6×4(12)3 help pls cncencenwevihbviubeuybtcqwctqgvcuqwcbucqwnbnu

Zanzabum

Answer:

42 - 24 * 36

18*36

and rewrite your answer by yourself

7 0

3 years ago

21 fewer stars than 3 times a number H

Ilya [14]

You get the expression;
3H-21
Hope this helps.

7 0

3 years ago