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SashulF [63]
3 years ago
11

In an experiment to see if light affected the amount of interaction, one group of students was put in a lighted room for an hour

, and another group was put in a room that was totally dark. Cameras recorded the n in each group. The independent variable in this experiment was?
Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
The Amount of light. 
dimulka [17.4K]3 years ago
4 0

Answer:

The amount of light is an independent variable.

Step-by-step explanation:

Consider the provided information.

The independent variable is the variable that the experimenter changes or controls to test the dependent variable impacts.

A dependent variable is the variable that depends on the independent variable and that the experimenter is testing and measuring.

For example:

In a study to determine whether how long you practice affects your game, the independent variable is the time you spent on practice while the dependent variable is the affects on your game.

Now consider the provided information.

In an experiment to see if light affected the amount of interaction, one group of students was put in a lighted room for an hour, and another group was put in a room that was totally dark. Cameras recorded the n in each group.

Here, the light is controlled by the experimenter but affect of interaction is dependents on light.

Thus, the amount of light is an independent variable.

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What two numbers add up to 6 and multiply to 12?
GuDViN [60]
Erm

x+y=6
xy=12


x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}
x= \frac{6+/- \sqrt{36-48} }{2}
x= \frac{6+/- \sqrt{-12} }{2}
x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}
x= \frac{6+/- (i)(2\sqrt{3}) }{2}
x= \frac{6+/- 2i\sqrt{3} }{2}
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho
7 0
3 years ago
Help me ASAP PLEASE
lina2011 [118]

Answer:

  4. Functions: 1, 2, 4, 5, 7, 8, 11, 12

  5. y = -1/2x+5/2, x ≤ -1; 2x +1, x > -1.

      y = 2, x < 0; x, 0 ≤ x ≤ 3; 3 x > 3.

Step-by-step explanation:

4. A list of ordered pairs is a function of no x-values are re-used. In (3) and (6), the value x=2 is used more than once.

A graph represents a function if it passes the "vertical line test." A vertical line cannot intersect the graph in 2 or more points. (9) and (10) both fail that test.

If the relation is not listed here as being "not a function," then it is one of the answers to question 4.

__

5. The first step in writing the equation of a piecewise function is to identify the pieces. These are generally bounded by points of discontinuity--jumps in the function value, or changes in the slope of lines.

The second step is to identify the section of the function that boundary points belong to. Solid dots are part of the function definition; open circles are not.

<u>Left Graph</u>

The left piece ends at x=-1. There is a solid dot attached to the left piece, so its definition will be for the domain x ≤ -1. That line has slope -1/2, since is drops 1 unit for each 2 to the right. If extended, it would intersect the y-axis at y = 2 1/2 = 5/2. So, the piece on the left is y = -1/2x + 5/2 for x ≤ -1.

The right piece starts at x=-1, but does not include that point. It has a rise of 2 for each 1 to the right, so its slope is 2. It crosses the y-axis at y=1, so the piece on the right is y = 2x + 1 for x > -1.

You can use the method of your textbook author to combine theses pieces into one equation. The method shown above is one way to do it.

__

<u>Right Graph</u>

This graph has a discontinuity at x=0 and a change in slope at x=3. It can be described by 3 pieces. The point at x=0 does not belong to the left piece, but goes with the middle piece.

The left piece of the function is the constant 2, so has the equation y = 2 for x < 0.

The middle piece has a slope of 1 and a y-intercept of 0, so has the equation y = x for 0 ≤ x ≤ 3.

The point at x=3 belongs to both the middle piece and the right piece, so can be part of both function definitions, if you like. Generally, it is better form to include any given x-value in only one of the pieces of the function. So the equation for the right piece can be y = 3 for x > 3.

4 0
3 years ago
Factor completely. 6x^2-18x-60
kogti [31]

Answer:

6(x+2)(x-5)

Step-by-step explanation:

6 0
3 years ago
Simplify the expressions and evaluate for (i) y = -2, (ii) y = 3.<br> 3y (2y-7) - 3 (y - 4) - 63
Diano4ka-milaya [45]

Simplified expression is 6y² - 24y - 51. Value for y=-2 is 21 and value for y=3 is  -69.

Step-by-step explanation:

  • Step 1: Given expression is 3y(2y-7) - 3(y - 4) - 63. Simplify it.

⇒ 6y² - 21y - 3y + 12 - 63

⇒ 6y² - 24y - 51

  • Step 2: Find value of the expression for y = -2

⇒ 6y² - 24y - 51 = 6(-2)² - 24(-2) - 51 = 24 + 48 - 51 = 21

  • Step 3: Find value of the expression for y = 3

⇒ ⇒ 6y² - 24y - 51 = 6(3)² - 24(3) - 51 = 54 - 72 - 51 = -69

8 0
3 years ago
Show me how to do the steps to solve this math problem: Tom has a can of paint that covers 37 1/2 square meters.Each board on th
ki77a [65]
He can paint 200 boards
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3 years ago
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