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Flauer [41]
3 years ago
5

Lindsey earns $15 per hour for the first 40 hours she works in a week and 50% more for every hour over 40. How many hours did Li

ndsey work in a week when she was paid $937.50 before taxes?
A. 15 hours
B. 30 hours
C. 40 hours
D. 45 hours
E. 55 hours​
Mathematics
1 answer:
solmaris [256]3 years ago
7 0

Answer:

E. 55 hours.

Step by step:

Multiple $15x40, equals $600

Subtract $600 from $937.50, equals $337.50

50% more over 40 hours is $22.50

Divide $337.50 by $22.50, equals 15

Add 15 to 40, equals 45

So she worked 55 hours to get paid $937.50

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2 years ago
Please help and thank you
ICE Princess25 [194]

Answer:

30

Step-by-step explanation:

15/3=5

5 x 5 = 25

25 + 5 = 30

4 0
3 years ago
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The surface area of a cylinder is 602.88. If the dimensions of the cylinder are
lana66690 [7]

Answer:

you all have to divide by 2

Step-by-step explanation:

602.88÷2= 301.44

3 0
3 years ago
Shannon is selling boxes cookies and candy for a fundraiser. She's sold each box of cookies for $5.25. She also sold one one box
defon

Answer:

The minimum boxes of cookies is 39

Step-by-step explanation:

Let

x ----> the number of boxes of cookies sold

y ----> the number of boxes of candies sold

we know that

The word "at least" means "greater than or equal to"

so

The inequality that represent this problem is

5.25x+8.75y\geq 200

The solution is the shaded area above the solid line   5.25x+8.75y=200

using a graphing tool

The solution is the shaded area -----> see the attached figure

Find out the minimum boxes of cookies needed to sell to reach the goal

assuming only cookies are sold

For y=0

5.25x+8.75(0)\geq 200

5.25x\geq 200

solve for x

x\geq 38.1

Round up

therefore

The minimum boxes of cookies is 39

5 0
3 years ago
Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t
Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3  6  10  12  15

2 | 3  3   5   6  15

3 | 3  3   5   3  15

5 | 1    1  5   1    5

  | 1    1   1   1     1

LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5

LCM(3, 6, 10, 12,15)=60

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0
3 years ago
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