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stealth61 [152]
4 years ago
13

A cylinder has a height of 6 cm and a radius of 2 cm. What is the volume of the cylinder?

Mathematics
2 answers:
iren [92.7K]4 years ago
8 0
Volume of cylinder =Π r^2 h
where 'r' refers to radius and 'h' refers to height of the cylinder
volume of cylinder = Π (2)^2 (6)
= Π (4)(6)
=Π (24)
75.36 cm^3 is the volume of the cylinder.

GuDViN [60]4 years ago
8 0
The volume of a cylinder is:

V=hπr^2  in this case h=6 and r=2 so

V=24π cm^3

V≈75.4 cm^3
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A recent survey found that 65% of high school students were currently enrolled in a math class, 43% were currently enrolled in a
Bas_tet [7]
<h3>Answer: Choice A)  0.20</h3>

===================================================

Explanation:

Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.

  • 65% of them are in math. So there are 0.65*1000 = 650 math students.
  • 43% are in science, leading to 0.43*1000 = 430 science students.
  • 13% are in both so we have 0.13*1000 = 130 students who are in both.

Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"

This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.

Of those 650 math students, 130 are also in science (since 130 are in both classes).

The probability we're after is therefore 130/650 = 0.20

4 0
3 years ago
Read 2 more answers
One end of a line segment has the coordinates (1, 3). If the
Paul [167]

Answer:

the answer is the letter D

8 0
3 years ago
Given sinx=3/5 and x is in quadrant 2, what is the value of tan(x/2)
xxMikexx [17]
X is in the second quadrant means that x/2 is in the first quadrant.


Consider the right triangle drawn in the figure. Let tan(x/2)=a.

Then, let the length of the opposite side to x/2 be a, the adjacent side be 1 and the hypotenuse be square root of a squared +1, as shown in the figure.

sin(x/2)=|opp side|/ |hypotenuse| =  \frac{a}{ \sqrt{ a^{2}+1 } }

cos (x/2) = |adj side|/ |hypotenuse| =  \frac{1}{ \sqrt{ a^{2}+1 } }


from the famous identity: sin(2a)=2sin(a)cos(a), we have:

2sin(x/2)cos (x/2)=sin(x)

thus

2* \frac{a}{ \sqrt{ a^{2}+1 } }*\frac{1}{ \sqrt{ a^{2}+1 } }= \frac{3}{5}

2* \frac{a}{  a^{2}+1 }= \frac{3}{5}

10a=3 a^{2} +3

3 a^{2}-10a +3=0

(3a-1)(a-3)=0

thus a=1/3 or a=3


thus tan(x/2)=1/3 or tan(x/2)=3


Answer: {1/3, 3}

3 0
3 years ago
Read 2 more answers
I need help on these questions
Kay [80]
1.) 10c - 12 = -2
-2C is the temperature in Tallahassee

2.) 48 kilometers divided the average of 3.2 Km
48÷3.2=15
15 is the value of D

3.) You seem to have 3 =D

4.) I'm pretty sure you just add \frac{1}{4} +  \frac{1}{3} =  \frac{7}{12}
7/12 is your answer

----------------------------------------------------------------------------------------------------------------
Thank You! Have a great day =D
and please correct me if wrong =D
7 0
3 years ago
Suppose e(x) = 3 and e[x(x − 1)] = 27.5. (a) what is e(x2)? [hint: first verify that e[x(x − 1)] = e[x2 − x] = e(x2) − e(x).]
Crank
52(ex) would be your answer 
6 0
3 years ago
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