All categories

3 years ago

Which function does the graph represent?

1 answer:

8 0

Answer: imgurl=http%3A%2F%2Fwww.rasmus.is%2FIS%2FT%2FF%2FSu52k03_m01.gif&imgrefurl=http%3A%2F%2Fwww.rasmus.is%2Fuk%2Ft%2FF%2FSu52k03.htm&tbnid=0mYNOM8hE-8CkM&vet=12ahUKEwj4y9mb3NrvAhXNtFMKHZ9kCDEQMygIegUIARCjAQ..i&docid=Iv4G7-Ojzx0JrM&w=290&h=247&q=Which%20function%20does%20the%20graph%20represent%3F3%2C%2015)Of(x)%20%3D%20(x%20%2B%203)(x%20%2B%207)O%20f(x)%20%3D%20(x%20-%203)(x%20-%207)O%20f(x)%20%3D%203(x%20%E2%80%93%203)(x%20%E2%80%93%207)Of(x)%20%3D%2011(x%20%2B%203)(x%20%2B%207)&safe=active&ved=2ahUKEwj4y9mb3NrvAhXNtFMKHZ9kCDEQMygIegUIARCjAQ

You might be interested in

Solve for the sides. WIll give brainliest if done in the next 10 minutes and is right

Volgvan

Answer:

x=8 and y=17

Step-by-step explanation:

hope this helps

3 0

3 years ago

URGENT <br> WILL GIVE BRAINLIEST <br> solve using matrices<br> 4x + 5y = 40 <br> x – y = 1

dalvyx [7]

Answer:

x = 5, y = 4

Step-by-step explanation:

$\left\{\begin{array}{ccc}4x+5y=40\\x-y=1\end{array}\right\\\\A=\left[\begin{array}{ccc}4&5\\1&-1\end{array}\right]\\\\detA=\left|\begin{array}{ccc}4&5\\1&-1\end{array}\right|=(4)(-1)-(1)(5)=-4-5=-9\\\\A^D=\left[\begin{array}{ccc}-1&-1\\-5&4\end{array}\right]\\\\\left(A^D\right)^T=\left[\begin{array}{ccc}-1&-5\\-1&4\end{array}\right]$

$A^{-1}=\dfrac{1}{detA}\left(A^D\right)^T\\\\A^{-1}=\dfrac{1}{-9}\left[\begin{array}{ccc}-1&-5\\-1&4\end{array}\right]=\left[\begin{array}{ccc}\dfrac{1}{9}&\dfrac{5}{9}\\\dfrac{1}{9}&-\dfrac{4}{9}\end{array}\right]$

$A\cdot\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}40\\1\end{array}\right] \\\\A^{-1}A\cdot\left[\begin{array}{ccc}x\\y\end{array}\right] =A^{-1}\cdot\left[\begin{array}{ccc}40\\1\end{array}\right] \\\\\left[\begin{array}{ccc}x\\y\end{array}\right] =A^{-1}\cdot\left[\begin{array}{ccc}40\\1\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}\dfrac{1}{9}&\dfrac{5}{9}\\\dfrac{1}{9}&-\dfrac{4}{9}\end{array}\right]\cdot\left[\begin{array}{ccc}40\\1\end{array}\right] \\\\\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}\left(\frac{1}{9}\right)(40)+\left(\frac{5}{9}\right)(1)\\\\\left(\frac{1}{9}\right)(40)+\left(-\frac{4}{9}\right)(1)\end{array}\right]\\\\\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}5\\4\end{array}\right]\Rightarrow x=5,\ y=4$

3 0

3 years ago

HELP!!!!!!!! 15 POINTS

IrinaK [193]

Answer:

x=5 is in the domain

Step-by-step explanation:

sqrt(x-5) ≥ 0

Square each side

(sqrt(x-5))^2 ≥ 0^2

x-5≥0

x≥5

This is the domain of x

3 0

3 years ago

A cylinder has a radius of 3.5. inches. what is the base area of the cylinder

Aleks [24]

Answer:

The formula for area of a circle is A = tt r^2

So 3.14 * 3.5^2 = 38.5

Step-by-step explanation:

8 0

3 years ago

35 cm

34kurt

Answer:

I think it might be B.) Triangle B

Step-by-step explanation:

6 0

3 years ago