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Vesna [10]
3 years ago
9

35 cm

Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

I think it might be B.) Triangle B

Step-by-step explanation:

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Which relation does not represent a function? A) a vertical line B) y = 5 9 x - 3 C) a horizontal line D) {(1, 7), (3,7), (5, 7)
Alisiya [41]

Answer:

A) a vertical line does not represent a function.

Step-by-step explanation:

For a relation to be a function for each value of x there must be only one value of y. In other words a function is one in which each value in the domain set corresponds to only one value in the range set.

Let us check for this condition in the give choices:

A) a vertical line

A vertical line is given as x=a which meas it is parallel to y-axis and has infinite number of y values for a single x value.

So, its Not a function

B) y=\frac{5}{9}x-3

For the given equation, on plugging in some x value will give a single y value.

So, its a Function

C) a horizontal line

A horizontal line is given as y=a which meas it is parallel to x-axis and has infinite number of x values giving a single y value.

So, its a Function

D) {(1, 7), (3,7), (5, 7), (7,7)}

For the given set for different x valuesthere is only one y value.

So, its a Function

4 0
3 years ago
Read 2 more answers
At holiday camp the ration of boys to girls
docker41 [41]

Answer:

Boys :girls!

Step-by-step explanation:

Plz write complete question

8 0
3 years ago
Solve the inequality. Explain all steps and identify the properties used. 3a-4<_ 5
Ierofanga [76]
Well, you want to solve for a. You first add the 4 to both sides. 
3a-4<5
3a<9
Then you want to get a by itself so you divide both sides by 3. Since the 3 is positive you don't have to worry about switching the sign. It stays this way <

After you divided both sides by 3 you get a<3
3 0
3 years ago
Solve the system of linear equations by elimination x + 2y = 13 --x+y=5​
katen-ka-za [31]

Answer:

{x,y} = {1,6}  Have a great day

5 0
3 years ago
Read 2 more answers
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
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