Anyone can help me with math for solving for a side in the right triangles for khan academy

Mathematics

1 answer:

Elden [556K]2 years ago

6 0

Answer:

7.45

Step-by-step explanation:

We are given a right triangle with one side length known and an angle know so we can use some trigonometry.

You need to find the hypotenuse so you are going to use either sine or cosine.

Since the adjacent from the angle is given (SOH-CAH-TOA) we can use cosine so,

cos(20) = 7/h

=>h = 7/cos(20)

=> 7.44924

=> 7.45

You might be interested in

What type of slope is shown?

kakasveta [241]

Answer:

Negative

Step-by-step explanation:

It going down starting from the left to right . Positive would be the other way around and zero would be side to side while undefined would be an up and down line .

5 0

3 years ago

Incorrect 00:00 Evaluate the expression for x = 1.7. Enter your answer in the box. х2 + 3x

IrinaK [193]

Answer:

7.99

Step-by-step explanation:

x^2 +3x

Let x=1.7

(1.7)^2 +3(1.7)

2.89+5.1

7.99

5 0

2 years ago

The football coach is overseeing the installation of new goal posts on the football field. He is wondering if the goal posts are

Westkost [7]

Answer:

Correct option is D. No, since the ratios of the corresponding sides are not proportional.

Step-by-step explanation:

Please refer to the attached figure

Let height of coach represents by AB = 6 feet

And shadow of coach represents by BC = 4 feet

Let height of goal post represents by DE = x feet

And Shadow of goal post represents by EF = 12 feet.

Since measurement of shadows are at same time. therefore ratio of height of coach and height of goal post must be same as ratio of shadow of coach and shadow of goal post.

⇒ 6/x = 4/12

⇒x = 72/4 = 18 feet

So goal post is not at regular height , since expected height is 20 feet while actual height is 18 feet . And if we consider value of x as 20 feet instead of 18 feet , ratio of corresponding sides will not match.

Hence correct answer is D. No, since the ratios of the corresponding sides are not proportional.