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Softa [21]
3 years ago
12

Anyone can help me with math for solving for a side in the right triangles for khan academy

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

7.45

Step-by-step explanation:

We are given a right triangle with one side length known and an angle know so we can use some trigonometry.

You need to find the hypotenuse so you are going to use either sine or cosine.

Since the adjacent from the angle is given (SOH-CAH-TOA) we can use cosine so,

cos(20) = 7/h

=>h = 7/cos(20)

=> 7.44924

=> 7.45

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The Volume of a sphare is 28/3 times the surface area calculate The surface area and the Volume of the sphere, correct to the ne
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Given:

Volume of a sphere is \dfrac{28}{3} times the surface area.

To find:

The surface area and the volume of the sphere.

Solution:

Volume of a sphere:

V=\dfrac{4}{3}\pi r^3              ...(i)

Surface area of a sphere:

A=4\pi r^2                      ...(ii)

Where, r is the radius of the sphere.

Volume of a sphere is \dfrac{28}{3} times the surface area.

V=\dfrac{28}{3}\times A

\dfrac{4}{3}\pi r^3=\dfrac{28}{3}\times 4\pi r^2

Multiply both sides by 3.

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\dfrac{\pi r^3}{\pi r^2}=\dfrac{112}{4}

r=28

Using (i), the volume of the sphere is:

V=\dfrac{4}{3}\times \dfrac{22}{7}\times (28)^3

V\approx 91989

Using (ii), the surface area of the sphere is:

A=4\times \dfrac{22}{7}\times (28)^2

A=9856

Therefore, the surface area of the sphere is 9856 sq. units and the volume of the sphere is 91989 cubic units.

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