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Softa [21]
3 years ago
12

Anyone can help me with math for solving for a side in the right triangles for khan academy

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

7.45

Step-by-step explanation:

We are given a right triangle with one side length known and an angle know so we can use some trigonometry.

You need to find the hypotenuse so you are going to use either sine or cosine.

Since the adjacent from the angle is given (SOH-CAH-TOA) we can use cosine so,

cos(20) = 7/h

=>h = 7/cos(20)

=> 7.44924

=> 7.45

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a certain virus infects one in every 600 people. a test used to detect the virus in a person is positive 90% of the time if the
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  1. the probability that a person has the virus given that they have tested positive is  0.0151.
  2. the probability that a person does not have the virus given that they have tested negative is  0.9999

P(A) = 1/600 = 0.0017

P(B) = 0.9 * 0.0017 + 0.1 * (1 - 0.0017) = 0.1014

A) P (has the virus | tested positive) = P (tested positive | has the virus) ×  

                                                          P (has the virus)/ P (tested positive)

                                                         = 0.9 × 0.0017/0.1014  

                                                         = 0.0151

B) P (does not have the virus | tested negative) = P (tested negative | does not have the virus) × P (does not have the virus)/ P (tested negative)

= (1 - 0.1) *× (1 - 0.0017)/ (1 - 0.1014)  

= 0.9999

Probability is the department of mathematics regarding numerical descriptions of ways likely an occasion is to occur, or how possibly it's far that a proposition is genuine. The possibility of an occasion varies between zero and 1, wherein, roughly speaking, 0 suggests the impossibility of the occasion and 1 shows certainty. The better the possibility of an event, the more likely it is that the event will arise.  

A simple instance is the tossing of an honest (unbiased) coin. since the coin is truthful, the 2 results ("heads" and "tails") are both equally likely; the possibility of "heads" equals the chance of "tails"; and considering the fact that no different results are feasible, the possibility of both "heads" or "tails" is 1/2 (that could additionally be written as 0.5 or 50%).

To learn more about Probability visit here:

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