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juin [17]
2 years ago
11

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
frozen [14]2 years ago
4 0

Answer:

8m^2

Step-by-step explanation:

1. 1*2=2m (add two of the triangles together)

2. 2*3=6m(same as the last step)

3. 6+2=8m (add them together)

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Your slope would be -1/4x. If you look at the y-intercept on your graph, which is -2, you would start to count up one box and over 4 boxes to the left. We call this rise/run. So knowing what the slope is now, your entire equation would be            y= -1/4x - 2. (Also, if the line is going up towards the left it is a negative slope, if it's to the right it is positive.) I hope this helps love! :) 
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3 years ago
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xz_007 [3.2K]

Answer:

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According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s
BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

  • a distribution is said be a binomial distribution iff
  1. The probability of success of that event( let it be p) is same for every trial
  2. each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
  3. there are fixed number of trials (n)
  4. the trials are independent
  • here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
  • here n=250
  • the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

  • \mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5

[since, the formula for \mu _{p} =n*p ]

  • \sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

  • therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

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3 years ago
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Svetllana [295]
I wish I could help but but I can't I'm dumb as a box of rocks
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A point that varies greatly from all other data points
Tju [1.3M]

Answer:

Outlier

Step-by-step explanation:

Very simple. No explanation.

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