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suter [353]
3 years ago
12

Tiffany starts walking her dog at 1:39 p.M. She gets back home at 2:28 p.M. How long did Tiffany walk her dog?

Mathematics
2 answers:
Tomtit [17]3 years ago
4 0

Answer:

49 minutes

Step-by-step explanation:

Given :

Start time = 1:39 p. M

Return time = 2.28 p. M

Time spent Walking dog = difference between the start time and return time

Return time - start time

(2:28 p.m - 1:39p.m) = 49 minutes

Hence, Tiffany spent 49 minutes walking her dog

meriva3 years ago
3 0

Answer:

dfsdddddddddd

Step-by-step explanation:

dfssssssssssssssssssssss\sqrt{x}

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Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
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Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

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Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

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\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

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What property is shown below?
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C.  Transitive Property

Step-by-step explanation:

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